Sujit runs at 6 km/hour and Rana at 8 km/hour .Rana catches Sujit in 9 minutes.What was the distance between sujit and Rana, when Rana started?

Answers

Answer 1
Answer:

The initial distance between Sujit and Rana, when Rana started, was 300 meters.

Let's first convert the time of 9 minutes into hours:

1 minute = 1/60 hours

9 minutes = 9/60 hours = 0.15 hours

Now, let's assume that Rana started at a distance of "x" kilometers from Sujit.

When Rana catches Sujit, they both would have covered the same distance.

The distance covered is equal to the product of their respective speeds and time taken:

Distance covered by Sujit = 6 km/hour × 0.15 hours = 0.9 km

Distance covered by Rana = 8 km/hour × 0.15 hours = 1.2 km

Now, we know that when Rana catches Sujit, the distance between them is equal to 0 km, as they meet at the same point. So, the difference in their distances is equal to the initial distance between them:

Initial distance between Sujit and Rana = Distance covered by Rana - Distance covered by Sujit

Initial distance between Sujit and Rana = 1.2 km - 0.9 km

= 0.3 km

Now, we need to convert this distance from kilometers to meters:

1 km = 1000 m

0.3 km = 0.3 × 1000 m

0.3km = 300 m

So, the initialdistance between Sujit and Rana, when Rana started, was 300 meters.

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Answer 2
Answer: 1 he and 51 minutes
I think its correct
if its not than sorry

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Answers

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Answers

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