A 6(6+8)
B. 12(3+4)
C. 2(18-24)
D. 419-12
The planes ABFE and EFGH intersected by line EF.
A prism is a polyhedron in geometry made up of an n-sidedpolygon basis, a second base that is a rigidly translated copy of the first base, and n additional faces that must all be parallelograms and connect the corresponding sides of the two bases.
We have cuboidal prism which have faces ABFE and EFGH.
To find the point for intersecting we have to find a point or line which is common in both planes.
Here the point E and F are common.
But the plane EF is also common
Thus, the intersecting line is line EF.
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Answer:
Line EF
Step-by-step explanation:
Planes intersect at lines
I need this ASAP
Answer:
65%
Step-by-step explanation:
You start by dividing 641.29 by 986.60 (641.29/986.60). This gets you .65, which as a percentage is 65%
Answer:
Wavelengths of all possible photons are;
λ1 = 9.492 × 10^(-8) m
λ2 = 1.28 × 10^(-6) m
λ3 = 1.28 × 10^(-6) m
λ4 = 4.04 × 10^(-6) m
Step-by-step explanation:
We can calculate the wavelength of all the possible photons emitted by the electron during this transition using Rydeberg's equation.
It's given by;
1/λ = R(1/(n_f)² - 1/(n_i)²)
Where;
λ is wavelength
R is Rydberg's constant = 1.0974 × 10^(7) /m
n_f is the final energy level = 1,2,3,4
n_i is the initial energy level = 5
At n_f = 1,.we have;
1/λ = (1.0974 × 10^(7))(1/(1)² - 1/(5)²)
1/λ = 10535040
λ = 1/10535040
λ = 9.492 × 10^(-8) m
At n_f = 2,.we have;
1/λ = (1.0974 × 10^(7))(1/(2)² - 1/(5)²)
1/λ = (1.0974 × 10^(7))(0.21)
1/λ = 2304540
λ = 1/2304540
λ = 4.34 × 10^(-7) m
At n_f = 3, we have;
1/λ = (1.0974 × 10^(7))(1/(3)² - 1/(5)²)
1/λ = (1.0974 × 10^(7))(0.07111)
1/λ = 780373.3333333334
λ = 1/780373.3333333334
λ = 1.28 × 10^(-6) m
At n_f = 4, we have;
1/λ = (1.0974 × 10^(7))(1/(4)² - 1/(5)²)
1/λ = (1.0974 × 10^(7))(0.0225)
1/λ = 246915
λ = 1/246915
λ = 4.04 × 10^(-6) m
Answer:
Hope this helps :)
Step-by-step explanation:
x+x-13=88
2x-13=88
2x-13+13=88+13
2x=101
101/2 = 50.5
Answer:
9x9+6 could be possible
Step-by-step explanation:
Hope this is what you were looking for, have a great day (;