MATHEMATICS MIDDLE SCHOOL

Given the geometric sequence where a1 = 3 and r = √2 find a9

Answers

Answer 1

Answer:

Answer:

$a_9=48$

Step-by-step explanation:

we are given

sequence is geometric

so, we can use nth term formula

$a_n=a_1(r)^(n-1)$

we have

$a_1=3$

$r=√(2)$

we have to find a9

so, we can plug n=9

we get

$a_9=3(√(2))^(9-1)$

$a_9=2^4\cdot \:3$

$a_9=48$

Answer 2

Answer:

Answer:

the answer to this geometric sequence is 48.

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Which number is greater, 134 or 143 ? Draw a picture ? How to draw a picture can you plz help ?

Answers

143 is to the right of 134, it means that 143 is greater than 134.

To compare the numbers 134 and 143 using a number line, you can create a horizontal line and place the numbers on it. Here's a step-by-step explanation:

Create a Horizontal Line: Draw a horizontal line to represent the number line. You can imagine this line to represent different values as you move from left to right.

0 1 2 3 4

|---|---|---|---|

Position the Numbers: On this line, you will place the numbers 134 and 143 at their respective positions.

Place "134" on the number line by marking the position for each digit. The "1" is at position 1, the "3" is at position 3, and the "4" is at position 4.

0 1 2 3 4

|---|---|---|---|

1 3 4

Now, place "143" on the number line in a similar way. The "1" is at position 1, the "4" is at position 4, and the "3" is at position 3.

0 1 2 3 4

|---|---|---|---|

1 4 3

Compare the Positions: Now that you have both numbers on the number line, you can visually compare their positions.

You can see that the number 143 is to the right of 134 on the number line.

Determine the Result: Because 143 is to the right of 134, it means that 143 is greater than 134.

0 1 2 3 4

|---|---|---|---|

134 143

Learn more about Number Comparison here:

brainly.com/question/29241034

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For 134 draw a block of 100, a block of 3 tens and 4 cubes

The function f(x)=-(x-3)^2 +9 can be used to represent the area of a rectangle with the perimeter of 12 units, as a function of the length of the rectangle, x. What is the maximum area of the rectangle?

Answers

Maximum area of the rectangle is $9cm^(2)$

Explanation:

Considering the dimensions to be in cm

$f(x) = -(x-3)^(2) +9\nf(x) = -(x^(2) +9 - 6x)+9\nf(x) = -x^(2) +6x\nf'(x) = -2x+6\n-2x+6 = 0\n2x=6\nx=3cm\n\n$

Putting the value of x = 3

$Perimeter = 2(x+b)\n12 = 2(3+b)\n6 = 3+b\nb= 3cm$

$Area of rectangle = x X b\n = 3 X 3\n = 9cm^(2)$

Therefore, maximum area of the rectangle is $9cm^(2)$

Could someone help me? 2/5 x 3/4

Answers

Answer:

im pretty sure the answer is 6/20

Step-by-step explanation:

Answer:

6/20 as a fraction

Step-by-step explanation:

Is the expression 2x-2 equivalent to the expression 2 (x-2)?Explain.

Answers

using the distributiver property which is
a(b+c)=ab+ac therefor
2(x-2)=2(x)+(2)(-2)
multiply
2x+-4
2x-4
2x-4=2x-2?
false

the answer is no

No, these are not equal because:-

2(x - 2) = 2*x - 2*2 = 2x - 4

2x - 2 is not equal to 2x - 4

Answer: Not equal

Which expression is equivalent to 1/4 (8 - 6x + 12)

Answers

first group the inners
1/4(8+12-6x)
1/4(16-6x)
distribute
4-3/2x

What number is 62% of 50

Answers

$62\% \ of \ 50= 62\% * 50=(62)/(100) * 50= (62)/(2) * 1=31$

31 is 62% of 50.

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Using pair and line graphs describe the difference between locating a point at 2,4 and 4,2

At 5 seconds, an object's velocity is 9 meters per second. At 8 seconds, the object's velocity is 25 meters per second. Assuming a constant acceleration, what is the acceleration in meters per second per second of the object? (If necessary, round to the nearest hundredth.)

PLEASE HELP ASAPIs the set of multiples of 4 closed under addition? Explain why or provide a counterexample if not. A. Yes, because the sum of any two multiples of 4 is also a multiple of 4. B. Yes, because the sum of any two multiples of 4 is also a multiple of 8. C. No, and a counterexample is –4 + (–8) = –12. D. No, and a counterexample is 26 + 16 = 42.