The hypotenuse of a right triangle is 7 inches, and one of the legs is square root 13 inches. Find the length of the other leg.A) 6 inches
B) square root 62 inches
C) square root 128 inches

Answers

Answer 1

Answer: The answer is A) 6 inches.
First I punch square root 13 in the calculator and got 3.6055... then I square the number since the formula has square root on it and got 13. Now the equation look something like this: 13 + b^2 = 49. 49 because 7^2 is 49. Then i subtract 49 by 13 and got 36. Now the equation look like this: b^2 = 36. After I square both side, I get b=6 in.

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Which of the following x-values makes the inequality -4x + 9 ≤ -23 true?

Can someone show me the steps to this equation. z- 4(2/3) = 2(2/3)
it read Z minus four and 2/3 equals two and two thirds just to clear confusion that the 2 and 4 are not being multiplied by 2/3

Answers

so z-4 2/3=2 2/3
so 4 2/3=12/3+2/3=14/3
2 2/3=6/3+2/3=8/3
z-14/3=8/3
multiply both sides by 3
3z-14=8
add 14 to both sides
3z=22
divide both sides by 3
z=22/3=7 1/3

$z-4(2)/(3)=2(2)/(3)\ \ \ \ |add\ 4(2)/(3)\ to\ both\ sides\n\nz=2(2)/(3)+4(2)/(3)\n\nz=6(4)/(3)\n\n\boxed{z=7(1)/(3)}$

The line segment that connects two nonconsecutive vertices in a polygon is called a

Answers

A line segment joining two adjacent vertices of a polygon is called an edge.

The line segment that connects two nonconsecutive vertices in a polygon is called a Diagonal i guess

Please help me asap i will help i

Answers

Answer:

x=20

Step-by-step explanation:

Ques5) x value is 20 because 3x+6x=180

=>9x=180

=> x=180/9

=> x=20

Ques6) 6x= 6*x which is equal to 6*20=120

Ques7) 3x=3*x which is equal to 3*20=60

This is correct because 120+20=180 which is a straight angle given in the question. Hope this helped, Thank you.

Answer:

the measurements must be incorrect because when you solve it, it is obvious that 6x is not a 90 degree angle and 3x is not 45 degrees.

Step-by-step explanation:

Solve 8m² + 20m = 12 for m by factoring

Please show all work

Answers

$8m^(2)+20m=12 / :2$
$4m^(2)+10m=6$
$4m^(2)+10m-6 =0$
$\Delta=b^(2)-4ac$
$\Delta=100-(4*4*-6)$
$\Delta=100+96=196$
$x1=(-b-√(\Delta))/(8)$
$x1=(-10-14)/(8)$
$x1=(-24)/(8)$
$x1=-3$
$x1=(-b+√(\Delta))/(8)$
$x2=(-10+14)/(8)$
$x2=(1)/(2)$

so you can write $8m^(2)+20m=12 / :2$ as

$8(m+3)(m-(1)/(2))=8*[m^(2)+2.5m-1.5]=0$

Please help due in a hour 20 points