What does 2/3 x 2 equal! Someone please help as soon as possible!

Answers

Answer 1
Answer: The first step we have to do is: 2/3 × 2. If it is multiplying a whole number to a fraction, multiply the whole number by the numerator. In this case, the numerator is 2, so we can do: 2 × 2 to get 4.

From multiplying, our new fraction would look like: 4/3. You can keep it as an improper fraction or you can turn it into a mixed fraction. To do so, divide the numerator by the denominator (4 ÷ 3) to get the answer of 1.3333, Keep the original denominator, write the remainder as the numerator, and whatever whole number you get, goes in front of the fraction. Since 4 ÷ 3 = 1 with a remainder of 1, we can keep the denominator, and switch out the numerator with 1, and also the whole number. 

The answer as an improper fraction: 4/3
The answer as a mixed fraction: 1 1/3
The answer as a decimal: 1.3333

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The product of 84.12 and which number will have three decimal places?A. 4.22 B. 10.51 C. 14.163 D. 19.3

Select each statement about the graph is true.

Answers

The answers are A, C, D I hope this helps mark me brainliest ❤


the answers to this would be a c and d

The combined age of three relatives is 120 years. James is three times the age of Dan, and Paul is two times the sum of James and Dan. How old is each relative

Answers

The ages of each relative are 30, 10 and 80 years respectively.

  • Let James' age be J.
  • Let Dan's age be D.
  • Let Paul's age be P.

Translating the word problem into an algebraic expression, we have;

J + D + P = 120 ......equation 1

J = 3D          .......equation 2

P = 2(J  + D)   ......equation 3

Substituting eqn 2 and 3 into eqn 1, we have;

3D + D + 2J + 2D = 120\n\n6D + 2(3D) = 120\n\n6D + 6D = 120\n\n12D = 120\n\nD = (120)/(12)

Dan, D = 10 years

For James;

J = 3(10)

James, J = 30 years.

For Paul;

P = 2(J  + D)

P = 2(30 + 10)\n\nP = 2(40)

Paul, P = 80 years.

Therefore, the ages of each relative are 30, 10 and 80 years respectively.

Read more: brainly.com/question/6463206

Answer: Your answer is 60

Step-by-step explanation:

How can I solve this system of linear equations by substitution 2x-3y=-24 and x+6y=18

Answers

to sub
solve for 1 variable
solve for x
minus 6y both sides on second equotn

x=18-6y

sub 18-6y for x in other equation
2(18-6y)-3y=-24
36-12y-3y=-24
36-15y=-24
minus 36 oth sides
-15y=-60
divide -15 both sides
y=4

sub back

x=18-6y
x=18-4(4)
x=18-16
x=2

x=2
y=4
(2,4)

Solve the inequality 6x − 8 > 4x + 26

Answers

Answer:

The solution for the inequality is x>17

Step-by-step explanation:

Consider the provided inequality.

6x - 8 > 4x + 26

Subtract 4x to both the sides.

6x -4x- 8 > 4x-4x + 26

2x- 8 > 26

Add 8 to the both sides.

2x- 8+8 > 26+8

2x > 34

Divide both the sides by 2.

x > 17

Hence, the solution for the inequality is x>17

Hi.

Answer:

\boxed{x>17}\checkmark

The answer should have positive sign but not negative.

Step-by-step explanation:

First, you add by 8 from both sides.

6x-8+8>4x+26+8

Then, simplify.

6x>4x+34

Next, you do is subtract by 4x from both sides.

6x-4x>4x+34-4x

Simplify.

2x>34

Therefore, you divide by 2 from both sides.

(2x)/(2)>(34)/(2)

Finally, you solve and simplify.

34/2=17

x=17\checkmark

X=17 is the correct answer.

Hope this helps you!

Have a nice day! :)

Need help fast answer with work shown

Answers

Answer:

(1) equilateral triangle

Step-by-step explanation:

Firstly, we will find all angles of triangle BCD

we are given

m<C=60

m<A=35

m<ABD=25

we know that sum of all angles in any triangle is 180

so, we get

m<A +m<ABD+m<DBC+m<C=180

we can plug values

35+25+m<DBC+60=180

m<DBC=180-120

m<DBC=60

now, we can find other angle

m<DBC+m<C+m<CDB=180

now, we can plug values

60+60+m<CDB=180

m<CDB=180-120

m<CDB=60

So, we can see that

m<C=m<DBC=m<CDB=60

so, all angles are equal

so, triangle BCD is an equilateral triangle


Kobe is drawing a net of a rectangular prism.How many rectangles should he draw if all the faces are rectangles?

Answers


He should draw six faces, since there are six faces on a rectangle.

he shold have 6 rectangels becase there is 4 rectangles and 2 squars squars are rectangels to or is it the other way arownd