On the xy-plane, the graph of function f has x-intercepts at -3, -1, and 1. which of the following could define f?A) f(x)= (x-3)(x-1)(x+1)
B) f(x)=(x-3)(x-1)^2
C) f(x)=(x-1)(x+1)(x+3)
D) f(x)=(x+1)^2(x+3)

Answers

Answer 1

Answer: x intercept is when y=0
or f(x) = 0
set the f(x)'s to 0
your answer is C
x-1=0 x+1=0 x+3=0
so x= -3, -1, and 1

Answer 2

Answer:

Final answer:

The function that defines f on the xy-plane with x-intercepts at -3, -1, and 1 is f(x)=(x+1)(x-1)(x+3), which is option C in the given options.

Explanation:

The question asks about a function on the xy-plane that has x-intercepts at -3, -1, and 1. The function's x-intercepts are the values of x where the function crosses or touches the x-axis, which means the function's value at that point (y) is zero. The general form of a polynomial that has roots (x-intercepts) at a, b, and c is given by f(x) = k(x - a)(x - b)(x - c) where k is a constant.

In this case the x-intercepts given are -3, -1, and 1, so we need to replace a with -3, b with -1 and c with 1 in the equation. so the correct function could be f(x) = k(x - (-3))(x - (-1))(x - 1). Simplifying this further gives f(x) = k(x + 3)(x + 1)(x - 1), which matches option C. Hence, option C is the equation that defines f.

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4|x+5|=20
Thanks for the help

Answers

4 |x = 5| = 20

First, divide both sides by 4. / Your problem should look like: $|x + 5| = 5$
Second, simplify $(20)/(4)$ to 5. / Your problem should look like: $|x + 5| = 5$
Third, break the problem into 2 equations. / x + 5 = 5 and -(x + 5) = 5
Fourth, solve x + 5 = 5. /
Cancel 5 on both sides. / $x = 0$
Fifth, solve -(x + 5) = 5 /
Simplify brackets / $-x - 5 = 5$
Add 5 to both sides / $-x = 5 + 5$
Add 5 + 5 / $-x = 10$
Multiply both sides by -1 / $x = -10$
x = -10
Sixth, collect the solutions to the problems. / Your problem should look like: $x = -10, 0$

Answer: x = -10, 0

4Ix+5I=20
$4(-(x+5))=20$
$4(-x-5)=20$ distributhing 4 through parantheses
$-4x-4*5=20$
$-4x-20=20$
$-4x=20+20$
$-4x=40$ divide by -4
$x= (40)/(-4)$ simplify
$x=-10$
The answer is : - 10

A train travels with a constant speed of 108 km/h. How long will it take to travel a distance of 270 kilometers? PLEASE HELLLLLLPPPP THERE BRAINLIEST

Answers

Answer:

The answer is 2.5 hours. That's how long it would take the train to travel 270 kilometers.

mark me brainliest!

6.
Is the line of reflection x, y, or z?

Answers

Answer:

The line of reflection is y.

Step-by-step explanation:

If it was reflection by the x axis, it would of been in the same position, just flipped around.

If it was reflection by the z axis, the two shapes would of been much closer (or further, depends how you look at it) than it is in graph.

Therefore, it is reflected by the y axis. You can also tell since both shapes are equidistant from the y axis.

Hope this helps!

Please help me out
(explain)
Thank You:)

Answers

The triangles are similar (proof of that is a different question), so the ratio of horizontal side to long side is the same for each.

$(5200\,ft)/(5600\,ft)=\frac{\text{??}}{7000\,ft+5600\,ft}\n\n(12600\,ft)\cdot(52)/(56)=\text{??}=11700\,ft$

The distance from A to E is 11,700 feet.

First prove that triangles ABD and ACE are similar (AA).

Then using corresponding sides of similar triangles are proportional, we can form the proportionality equation

AE/AC = AD/AB

=> AE/(7000+5600) = 5200/5600

Cross multiply,

AE=5200/5600*(12600)

=11700 feet

The weights (to the nearest pound) of some boxes to be shipped are found to be: Weight 65 68 69 70 71 72 90 95 frequency 1 2 5 8 7 3 2 2 Explain why or why not this could be represented by a bell curve (a normal distribution).

Answers

The given weights do not exhibit the characteristics of a bell curve or a normal distribution. The data is skewed, lacks a clear central tendency, and contains outliers. Therefore, it cannot be accurately represented by a normal distribution.

Here, we have,

To determine whether the given weights can be represented by a bell curve (normal distribution), we need to assess if the data exhibits the characteristics of a normal distribution.

Here are a few considerations:

Symmetry: A normal distribution is symmetric, meaning the data is equally distributed around the mean. In the given data, there are more observations on one side of the distribution (higher weights) than the other. This indicates a lack of symmetry, which is not characteristic of a bell curve.

Central tendency: A normal distribution typically has a single peak or mode at the center. In this case, there isn't a clear central tendency as the weights seem to be spread across different ranges without a dominant peak.

Outliers: Normal distributions tend to have minimal outliers or extreme values. The presence of weights like 90 and 95, which are noticeably higher than the other values, suggests the presence of outliers. This goes against the assumption of a bell curve.

Based on these considerations, it appears that the given weights do not exhibit the characteristics of a bell curve or a normal distribution. The data is skewed, lacks a clear central tendency, and contains outliers. Therefore, it cannot be accurately represented by a normal distribution.

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because the data is not a normal distribution because the second half of the data is too far away from the first half i think its also called unproportional or something like that feel free to add me as a friend

Evaluate j/4 when j=12