a third grade class is growing bean plants. the list below shows the height of the plants. use the information to complete the line plot

Answers

Answer 1

Answer: u need the rest of the info

Related Questions

Which relations are functions?Choose all answers that are correct.A.A curve that increases from left to right is plotted on a coordinate grid. The curve goes through point negative 2, negative 3, point negative 1, negative 1, point 0, 0, point 1, 1, and point 2, 3. B.x −2 0 3 5y 1 3 2 3C.A set of points are plotted on a coordinate grid. The points include point 5, 4, point 4, 1, point 3, 5, point 3, negative 2, point 2, 2, point 1, 0, and point negative 1, 3. D.{(−3, 5), (−1, 3), (2, 2), (2, 6)}
Help fill in the blanks plz
Do you know what this is 8 – 3k = 5?
Using a transit, a surveyor measures the angle between two trees to be 111 degrees. If the first tree is 62 feet from the transit and the second tree is 58 feet from the transit, what is the distance between the two trees?
Henry has a bag of marbles. six of them are striped. The other half of the marbles are not striped. How many marbles does Henry have?

How many ways can 3 students be chosen from a class of 20 to represent their class at a banquet?

Answers

Slot method 20 options 3 slots First slot: 20 options Second slot: 19 options (one used up for 1st slot) Third slot: 18 (one less than last) Multiply them 20 times 19 times 18=6840 Answer is 6840 ways

60 ways because the easy way to solve this problem is identify the numbers being used and than multiply them by each other.

The frequency polygon shows the distances thrown by the entrants in the University and College Discus Finals at the 2003 Drake Relays. What percent of the entrants had distances between 150 and 160 feet? Round your answer to two decimal places

Answers

Answer:

70.83% entrants will have distances between 150 and 160.

Step-by-step explanation:

This question is incomplete without an attachment; here is the attachment enclosed with the answer.

From the graph attached,

Number of entrants having distances between 150 and 160 feet = 8 + 9 = 17

Number of entrants between 140 and 200 feet = 8 + 9 + 4 + 2 + 1 = 24

Percent of entrants having distance between 150 and 160 feet = $\frac{\text{Number of entrants between 150 and 160}}{\text{Number of total entrants}}* 100$

= $(17)/(24)* 100$

= 70.83%

Therefore, 70.83% entrants will have distances between 150 and 160.

Final answer:

To find the percent of entrants with distances between 150 and 160 feet in the frequency polygon, calculate the area of the rectangle between the two values and divide it by the total area under the polygon. Multiply the result by 100 to get the percent.

Explanation:

To find the percent of entrants with distances between 150 and 160 feet, we need to look at the area under the frequency polygon between the two values. Since the frequency polygon represents the distribution of distances, we can estimate the percent by calculating the proportion of the area under the polygon between 150 and 160 feet. First, find the total area under the polygon by adding up the areas of all the rectangles formed by the frequency values and the width of each interval. Then, calculate the area of the rectangle between 150 and 160 feet by multiplying the frequency of that interval by its width. Finally, divide the area of the rectangle by the total area under the polygon and multiply by 100 to get the percent.

Example:

Total area under the polygon = Sum of (Frequency x Width) = (5 x 10) + (10 x 10) + (30 x 10) + (40 x 10) + (15 x 10) = 500
Area of rectangle between 150 and 160 feet = Frequency x Width = 40 x 10 = 400
Percent of entrants with distances between 150 and 160 feet = (Area of rectangle / Total area) x 100 = (400 / 500) x 100 = 80%

Learn more about frequency polygon here:

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Which of the following expressions are equivalent? Justify your reasoning.4√x3

1
x−1

10√x5•x4•x2

x
1
3
•x
1
3
•x
1
3

Answers

Answer:

b and d

Step-by-step explanation:

b. 1/x^-1

=(1/x)^-1

d. x^1/3 * x^1/3 * x^1/3

=x^1/3+1/3+1/3

=x^3/3

=x^1

=x....

Rewrite the expression below using the Associative Property of Multiplication: (ab)c

Answers

Answer:

hope this helps

Step-by-step explanation:

(ab)c = (ac)b = (bc)a

Answer:

Here are a couple of examples (a+b)c or (c+b)a or (a+c)b

Step-by-step explanation:

To “associate” means to connect or join with something. According to the associative property of multiplication, the product of three or more numbers remains the same regardless of how the numbers are grouped. Here's an example of how the product does not change irrespective of how the factors are grouped.

A regular hexagon (6-sided figure) has sides that are all the same length. Each side length is represented by the expression x + ⅓ y. a) Write an algebraic expression that represents the perimeter of the hexagon. b) Use one of the expressions and evaluate the perimeter of the hexagon if x = 5 and y = 6 HELPPPPP!!!!!

Answers

perimiter=6 times legnth of one side
P=6(x+1/3y)
P=6x+6/3y
P=6x+2y

if x=5 and y=6
P=6(5)+2(6)
P=30+12
P=42

A. P=6x+2y
B. 42 units is the perimiter

If 78 sit-ups is done in 2 minutes how many can be done in 5 minutes

Answers

In 5 minutes 195 sit ups can be done.

What is referred as the unitary method?

The unitary method is a process that determines the value of a single unit from value of multiple units, as well as the value of multiple units from of the value of a single unit.
It is a method for determining the value of a single unit by subtracting the value of multiple units and subtracting the value of different components from of the value of a single unit.

For the given question.

If 78 sit-ups is done in 2 minutes.

this can be written as;

2 minutes -------> 78 sit ups.

For 1 minutes, divide both side by 2.

1 minutes -------> 39 sit ups.

For 5 minutes, multiply both sides by 5.

5 minutes -------> 195 sit ups.

Thus, in 5 minutes 195 sit ups can be done.

To know more about the unitary method, here

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