MATHEMATICS COLLEGE

WILL GIVE BRAINLIEST Are 1/3 and 17/51 equal?

Answers

Answer 1

Answer:

Answer:

Yes

Step-by-step explanation:

51 ÷ 17 = 3

$((17)/(17))/((51)/(17) )=(1)/(3)$

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20 POINTS! Easy math questions, I just don't have time. ASAP PLEASE

Answers

She has $317.57
He fee would be $18

Help math math math

Answers

Answer:

Yes

Step-by-step explanation:

Answer:

The answer is Yes. Hope this helps :)

Step-by-step explanation:

The average starting salary of this year's vocational school graduates is $35,000 with a standard deviation of $5,000. Furthermore, it is known that the starting salaries are normally distributed. What are the minimum and the maximum starting salaries of the middle 95% of the graduates

Answers

Answer:

Minimum: $25,200

Maximum: $44,800

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu = 35000, \sigma = 5000$

What are the minimum and the maximum starting salaries of the middle 95% of the graduates

Minimum: 50 - (95/2) = 2.5th percentile.

Maximum: 50 + (95/2) = 97.5th percentile

2.5th percentile:

X when Z has a pvalue of 0.025. So X when Z = -1.96.

$Z = (X - \mu)/(\sigma)$

$-1.96 = (X - 35000)/(5000)$

$X - 35000 = -1.96*5000$

$X = 25200$

The minimum is $25,200

97.5th percentile:

X when Z has a pvalue of 0.975. So X when Z = 1.96.

$Z = (X - \mu)/(\sigma)$

$1.96 = (X - 35000)/(5000)$

$X - 35000 = 1.96*5000$

$X = 44800$

The maximum is $44,800

Test the following numbers for divisibility by 3, 5, 6 and 11. (Do not divide or factorise.) a) 68 979

Answers

Final answer:

The number 68,979 is divisible by 3 but not by 5, 6, or 11.

Explanation:

To test a number for divisibility by 3, we sum up its individual digits. If the sum is divisible by 3, then the number itself is divisible by 3. For the number 68,979, the sum of its digits is 6 + 8 + 9 + 7 + 9 = 39. Since 39 is divisible by 3, 68,979 is also divisible by 3.

To test a number for divisibility by 5, we simply check if the last digit is either 0 or 5. In the number 68,979, the last digit is 9, which is neither 0 nor 5. Therefore, 68,979 is not divisible by 5.

To test a number for divisibility by 6, we need to check if it is divisible by both 2 and 3. From the previous tests, we already know that 68,979 is divisible by 3, so we now need to check if it is divisible by 2. Since the last digit is 9, which is an odd number, 68,979 is not divisible by 2, and therefore not divisible by 6.

To test a number for divisibility by 11, we take the alternating sum of its digits. In this case, we have 6 - 8 + 9 - 7 + 9 = 9. Since 9 is not divisible by 11, 68,979 is not divisible by 11.