Ms. Hartland bought x number of shirts for the new members of her chorus. The cost for x number of shirts, including $3.99 shipping, was $77.49. Each shirt cost $12.25. There was no sales tax on this purchase. Which equation could be used to find x? A. 3.99(x+12.25) =77.49
B. 3.99x + 12.25 =77.49
C. 12.25(x+3.99) = 77.49
D. 12.25x+3.99= 77.49

Answers

Answer 1
Answer:

Answer:

D. 12.25x +3.99 = 77.49

Step-by-step explanation:



Related Questions

In a hat, you have index cards with the numbers 1 through 10 written on them. Find how many of the 10 possible numbers you can pick match the described event, then drag and drop each of the numbers into the correct box to order the events from least likely to happen (1) to most likely to happen (8) when you pick one card at random.A. You pick a number greater than 0. B. You pick an even number. C. You pick a number that is at least 2. D. You pick a number that is at most 0. E. You pick a number divisible by 3. F. You pick a number divisible by 5. G. You pick a prime number. H. You pick a number less than the greatest prime number among thenumbers 1 through 10.
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Solve and check. r\6=5 2\3a. 34b. 30 2\3 c. 20d. 17\18              ASAP

Last week Trent made 80 on his quiz. This week he made a 90. What is the percent of increase in his score? A.10%
B.12.5%
C.11%
D.15%

Answers

90=80x
x=9/8=1.125
.125*100=12.5%
(A)10%
because 10+80 equals 90

How many unique triangles can be made where one angle 60° and another angle is an obtuse angle?

Answers

That set of requirements narrows it down to only
an infinite number of possible unique triangles.

-- One angle is 60°.  That leaves 120° for the sum of the other two.

-- One angle is obtuse.  It can be anything more than 90°
and less than 120°.

-- And the third angle gets whatever is left.

-- If you don't mind fractional or decimal parts of degrees, then we
already have an infinite number of possible combinations of angles.
_____________________________________

Every possible combination of angles defines a unique set of
RATIOs among the sides.

But for EVERY unique set of RATIOs, there are an infinite number of possible unique triangles that are SIMILAR to each other.

Example:

If the angles determine that the sides must be in the ratio of 1:2:3,
then the triangle can have sides of

1, 2, and 3
2, 4, and 6
3, 6, and 9
4, 8, and 12
5, 10, and 15
6, 12, and 18
7, 14, and 21
8, 16, and 24
9, 18, and 27
10, 20, and 30
.
.
etc.

These all have the SAME set of ANGLES, and the same RATIO
among the sides, but they're all different unique triangles.

3.5 × 4 brainliest...

Answers

Answer:

14

Step-by-step explanation:

14

8/5 ×4 5/7 so how much fruit do I have all together

Answers

7.5 is the rounded amount. So about seven and a half pieces.
7_19/35
solve
convert 4_5/7 to 33/7
now multiply that by 8/5
8/5*33/7
8*33=264 
5*7=35
264/35
divide 264/35=7.542
converted to fraction it's 7_19/35

How do I transform the equations 5x+4y=8 and -2x+5y=30 so that they are in the form that y=MX+b?

Answers

4y=5x+8 5y=-2x+30 the y always goes first. then the equal sign. next is x and finally just the digit which is also known as "b".
Make y the subject for both equations: 

5x + 4y = 8
4y = -5x + 8 
y = -(4/5)x + 8

-2x + 5y = 30
5y = 2x + 30
y = (2/5)x + 6

There you go, both equations are in y = mx + b for :) 

A telephone pole has a wire attached to its top that is anchored to the ground. The distance from the bottom of the pole to the anchor point is 63feet less than the height of the pole. If the wire is to be 9

feet longer than the height of the pole, what is the height of the pole?

Answers

Answer:

Height of pole =108 feet

Step-by-step explanation:

Let height of the pole be= AB= x feet

Distance from bottom of the pole to anchor point =BC= x-63 feet

Length of wire =AC= x+9 feet

Applying Pythagorean theorem.

In the given \triangle ABC

AC^2=AB^+BC^2

Plugging in values of each.

(x+9)^2=x^2+(x-63)^2

Expanding the binomials using identities.

x^2+18x+81=x^2+x^2-126x-3969\n

Combining like terms.

x^2+18x+81=2x^2-126x+3969

Subtracting x^2 from both sides.

x^2-x^2+18x+81=2x^2-x^2-126x+3969

18x+81=x^2-126x+3969

Subtracting 18x+81 from both sides.

(18x+81)-18x-81=x^2-126x+3969-18x-81

0=x^2-144x+3888

We get the quadratic equation to solve.

x^2-144x+3888=0

Solving quadratic using formula:

x=(-b\pm√(b^2-4ac))/(2a)

Plugging in values.

x=(-(-144)\pm√((-144)^2-4(1)(3888)))/(2(1))

x=(144\pm√(20736-15552))/(2)

x=(144\pm√(5184))/(2)

x=(144\pm72)/(2)

x=(144\pm 72)/(2)

x=(144+72)/(2) and x=(144-72)/(2)

x=(216)/(2) and x=(72)/(2)

x=108 and x=36

Since distance from pole to anchor point is 63 feet less than the height of pole, thus the height of the pole has to be =108 feet