MATHEMATICS MIDDLE SCHOOL

About 5.67811 X10^5 liters of water flow over Niagara Falls per second there are 3.15576 x10^7 seconds in one year the number of liters of water that flows over Niagara Falls each year are about 5.67811 x 10^5 x3.15476x10^7A.1e12
B. 179187524.1
C.1.791875241e13
D. 1.92559524e-44

Answers

Answer 1
Answer:

Answer:

C.  1.791875241e13

Step-by-step explanation:

We have that,

Amount of water flows over Niagara Falls per second = 5.67811×10⁵

Also, the number of seconds in a year = 3.15576×10⁷

Thus,

Liters of water that flows in a year = Amount of water that flows × Number of seconds

i.e. Liters of water = 5.67811 × 10⁵ × 3.15576 × 10⁷

i.e. Liters of water = 17.91875241 × 10¹²

i.e. Liters of water = 1.791875241 × 10¹³

Hence, the liters of water that flows through Niagara Falls each year is 1.791875241 × 10¹³ i.e. 1.791875241e13
Answer 2
Answer:

Answer:

C-the one with e13

Step-by-step explanation: I just did it on i-ready and got it right. plz mark brainliest.

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the 175 anniversary of the completion of the erie canal was in the year 2000 if it took 8 years to dig the canal in what year did the digging of the erie canal begin?

216 as a power number

Answers

it would be 6^3 which is 6*6*6 = 216 :)
Hey There,

216 is equal to 6^(3)

Solution:

6*6*6=213

Thank You!

Can you please help me its too hard

Answers

Answer:

12

Step-by-step explanation:

The area of a rectangle is l × w.

x × 11/3 = 44

x = 44 × 3/11

x = 12
the area of this figure is 12

Three people are playing a computer game one person scored -8 second persons was 3/4 and the third persons was 1/4 what was Leah's score?

Answers


We can't tell with the given information.  We don't know if Leah was
one of the three people, or if she was even on the same planet while
they were playing the game.

The sides of a square are 3 cm long. One vertex of thesquare is at (2,0) on a square coordinate grid marked in
centimeter units. Which of the following points could
also be a vertex of the square?
F. (−4, 0)
G. ( 0, 1)
H. ( 1,−1)
J. ( 4, 1)
K. ( 5, 0)

Answers

Answer:  The required point that could also be a vertex of the square is K(5, 0).

Step-by-step explanation:  Given that the sides of a square are 3 cm long and one vertex of the  square is at (2,0) on a square coordinate grid marked in  centimeter units.

We are to select the co-ordinates of the point that could also be a vertex of the square.

To be a vertex of the given square, the distance between the point and the vertex at (2, 0) must be 3 cm.

Now, we will be suing the distance formula to calculate the lengths of the segment from the point to the vertex (2, 0).

If the point is F(-4, 0), then the length of the line segment will be

\ell=√((-4-2)^2+(0-0)^2)=√(6^2+0^2)=√(6^2)=6~\textup{cm}\neq 3~\textup{cm}.

If the point is G(0, 1), then the length of the line segment will be

\ell=√((0-2)^2+(1-0)^2)=√(2^2+1^2)=√(4+1)=\sqrt5~\textup{cm}\neq 3~\textup{cm}.

If the point is H(1, -1), then the length of the line segment will be

\ell=√((1-2)^2+(-1-0)^2)=√(1^2+1^2)=√(1+1)=\sqrt2~\textup{cm}\neq 3~\textup{cm}.

If the point is J(4, 1), then the length of the line segment will be

\ell=√((4-2)^2+(1-0)^2)=√(2^2+1^2)=√(4+1)=\sqrt5~\textup{cm}\neq 3~\textup{cm}.

If the point is K(5, 0), then the length of the line segment will be

\ell=√((5-2)^2+(0-0)^2)=√(3^2+0^2)=√(3^2)=3~\textup{cm}.

Thus, the required point that could also be a vertex of the square is K(5, 0).
K (5.0) It's easy just use 2plus3and that's it.

johns test grades in his science class are 82, 93, 75, and 89 what is his average? 1. (87.45) 2. (80.00) 3. (90.40) 4. (89.25) 5. (84.75)

Answers

Answer:

The average of the John scores is 84.75.

Step-by-step explanation:

Formula of average is given as :

A=\frac{\text{Sum of all the terms}}{\text{Number of terms}}

We have:

Test grades of John: 82, 93, 75, and 89

Number of terms - 4

Average of the score of the John;

a=(82 + 93 +75 + 89)/(4)=84.75

The average of the John scores is 84.75.

First you add all the numbers together. So you add 82+93+75+89 to get 339. Once you get that, you divide it by the amount of numbers there are. In this case, it's 4. 339 divided by 4 is 84.75.

HOPE THIS HELPS!!

ms.Holloway is putting up a bulletin board about frogs. The bulletin board is 6 feet wide and 4 feet tall. she wants to put a border around the board. what is the distance around the edge of the bulletin board?

Answers

The distance around the bulletin board would be 20 feet, because you multiply 6ft 2x and 4ft 2x.
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