What is the value of sin(−θ) ?Let cos(−θ)=−3/5 and tanθ>0 .

A. -4/5
B. 4/3
C. -3/5
D. 4/5

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

The cosine of a right triangle is the adjacent over the hypotenuse. If the cosine is -3/5 then it must be a right triangle with sides 3, 4, & 5 since this is a Pythagorean triple. This means the sin will be -4/5. We know its negative because the tangent is positive so this is the 3rd quadrant where both Sine and Cosine are negative.

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How to write 7/9 as a decimal
The table shows the distances and times that four people ran. Without making any calculations, who ran the fastest?

A souvenir mug sells for $8.00 at a hotel gift store. The sales tax on the mug is $0.44.What is the sales tax rate? (Remember, sales tax rate is a percent)

please help with this!!!

Answers

The sale tax rate is 5.5%
Proof : 8 x 5.5% = $8.44

Write and solve an equation to find the value of x and the missing angle measures.

Answers

7x + 18 = 8x + 7 bcuz they are alternate exterior angles
18-7 = 8x - 7x
11 = x

So the angle measures are
95 and 95

Answer:

x = 11 --> angles = 95 degrees

Step-by-step explanation:

They are equal to each other so

7x + 18 = 8x + 7

Put the like terms together

18 - 7 = 8x - 7x

11 = x

so when we substitute this value of x into the equations, we get that both angles are 95 degrees.

Hope this helps!

Consider the experiment of rolling a dice. Find the probability of getting an even number 3) and a number that is multiple of 3.

Answers

The required probability of rolling a dice and getting an even number and a number that is a multiple of 3 is 1/6.

To find the probability of rolling a dice and getting an even number (3, 4, or 6) and a number that is a multiple of 3 (3 or 6), we need to consider the outcomes that satisfy both conditions.

There are three even numbers on a standard six-sided dice: 2, 4, and 6. Out of these three even numbers, two of them are multiples of 3 (3 and 6).

The probability of rolling an even number is 3/6 (3 even numbers out of 6 possible outcomes) or simply 1/2.

The probability of rolling a number that is a multiple of 3 is 2/6 (2 multiples of 3 out of 6 possible outcomes) or 1/3.

Now, to find the probability of both events occurring together (rolling an even number and a number that is a multiple of 3), we multiply the individual probabilities:

Probability of getting an even number AND a number that is a multiple of 3 = (1/2) * (1/3) = 1/6.

So, the probability of rolling a dice and getting an even number and a number that is a multiple of 3 is 1/6.

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Which is the graph of g(x) = (0.5)x + 3 – 4?

Answers

Answer:

Graph (A)

Step-by-step explanation:

Given question is incomplete; find the question in the attachment.

Given function is g(x) = $(0.5)^(x+3)-4$

Parent function of the given function is,

f(x) = $(0.5)^(x)$

When the function 'f' is shifted by 3 units left over the x-axis, translated function will be,

h(x) = f(x+3) = $(0.5)^(x+3)$

When h(x) is shifted 4 units down, translated function will be,

g(x) = h(x) - 4

g(x) = $(0.5)^(x+3)-4$

g(x) has a y-intercept as (-4).

From the given graphs, Graph A shows the y-intercept as (-4).

Therefore, Graph A will be the answer.

Answer:

The Answer A is correct

Step-by-step explanation:

I took the edg2020 test

En una baraja de 52 cartas, donde hay 13 cartas de trébol. 13 cartas decorazones, 13 cartas de espadas y 13 cartas de rombos. Si sacamos dos
cartas con reemplazo. ¿Cuál es la probabilidad de que sean de
corazones?

Answers

Ya no clue sorry bro

A particle moving along a line has position s(t) = t^4 − 20t^2 m at time t seconds. Determine: (a)- At which times does the particle pass through the origin? (b)- At which times is the particle instantaneously motionless.

Answers

The particle passes through the origin at t = 0 and t = ±√20. The particle is instantaneously motionless at t = 0 and t = ±√10.

(a) To determine the times at which the particle passes through the origin, we need to find when the position function equals zero. So, we set s(t) = 0 and solve for t.
t4 - 20t2 = 0
Factoring out a t2, we get:
t2(t2 - 20) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial position), and t = ±√20 (approximately t = ±4.47).

(b) To determine when the particle is instantaneously motionless, we need to find when the velocity of the particle is equal to zero. The velocity function of the particle is the derivative of the position function. So, we differentiate s(t) with respect to t to find the velocity function.
v(t) = s'(t) = 4t³ -40t
Setting v(t) = 0, we have:
4t³ -40t = 0
Factoring out a 4t, we get:
4t(t² - 10) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial velocity), and t = ±√10 (approximately t = ±3.16).

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Final answer:

The particle passes through the origin at t = 0 and t = √20 seconds. The particle is instantaneously motionless at t = 0 and t = ±√10 seconds.

Explanation:

The position of the particle at time t is given by the equation s(t) = t4 - 20t2. To determine the times when the particle passes through the origin, we set s(t) equal to zero and solve for t. This gives us the quadratic equation t4 - 20t2 = 0, which can be factored as t2(t2 - 20) = 0. The solutions to this equation are t = 0 and t = ±√20. Since t cannot be negative in this scenario, the particle passes through the origin at t = 0 and t = √20 seconds.

To determine the times when the particle is instantaneously motionless, we need to find the times when the velocity of the particle is equal to zero. The velocity of the particle can be found by taking the derivative of the position function with respect to time, v(t) = 4t3 - 40t. Setting this equation equal to zero and solving for t gives us the cubic equation 4t3 - 40t = 0. This equation can be factored as 4t(t2 - 10) = 0. The solutions to this equation are t = 0 and t = ±√10. Therefore, the particle is instantaneously motionless at t = 0 and t = ±√10 seconds.