17/4/3/4 in simplest form
Answers
17/4*4/3
=17/3
Related Questions
Abigail redecorates her house. A scale drawing of her house can be seen below. If each 6 cm on the scale drawing equals 12 ft, what are the actual dimensions of Abigail's house. The scale numbers are 10 cm, 9 cm, 8 cm, 9 cm, and 7 cm.
What's an Easier way to find the Median in a Dot Plot?
Need help.Picture has it all..
how many 200 mL paper cups can be filled from a 2 liter jug of lemonade?
Answers
ANSWER:
The slope of the given equation is -2 and a point on the given line is (-1, 3)
SOLUTION:
Given, linear equation in two variables is y – 3 = -2(x + 1) ----- eqn (1)
We need to find the slope of the given equation and a point through which the given line passes.
Given equation is in the form of point slope form .i.e --- eqn 2
where,"m" is the slope of the line
is point on that line.
Now, by comparing (1) and (2)
m = -2
so, the slope of the given equation is -2 and a point on the given line is (-1, 3)
Answer: slope: − 2
y-intercept: ( 0 , 1 )
x y 0 1 1 − 1
Step-by-step explanation: Graph the line using the slope and y-intercept, or two points.
Answers
u can either add : 5/12 + 5/12 + 5/12 = 15/12 = 1 1/4 hrs
or u could multiply : 3 * 5/12 = 15/12 = 1 1/4 hs
either way....same answer
I need help PLEASE!
Answers
Convert your percentage into a decimal:
Multiply your decimal by 55:
Luisa mows lawns during the summer. She charges $15 if she cuts the grass but charges $5 more if she also trims the grass. Last week she trimmed 5 more yards than she cut. If she made $415 last week, how many yards did she trim?
Answers
Answer:
315÷35=9
Step-by-step explanation:
5 extra yards had given her an extra $100, so the yards she cut, plus those she trimmed, had given her $315. To cut one and trim another one she takes $35. This means 9 yards were cut and 14 trimmed. (315÷35=9)
Answers
1 km=100,000 cm
2.17 km=2.17×100,000=217,000 cm
Solve the system of equations.
Answers
2x + 3y = 1
y = 3x + 15
There's not much you can do with the first equation, because it has
two variables in it ... 'x' and 'y' . No matter how much you move them
around, you'll never be able to get either one equal to just a number.
Is there any way you could get rid of one of the variables in the first
equation, and have just 1 letter in it to solve for ?
Absolutely ! The second equation tells you something that 'y' is equal to,
(3x + 15). "EQUAL" is very powerful. It means that wherever you see 'y',
you can put (3x + 15) in its place, and you won't change anything or
upset anything. One thing you can do is take that (3x + 15) from the
2nd equation, and put it right into the first equation in place of 'y'.
You'll see how that helps as soon as you do it.
First equation: 2x + 3y = 1
Substitute for 'y' : 2x + 3(3x + 15) = 1
Remove parentheses: 2x + 3(3x) + 3(15) = 1
2x + 9x + 45 = 1
Combine the terms with 'x' in them: 11x + 45 = 1
Look what you have now ! An equation with only one variable in it !
Subtract 45 from each side: 11x = -44
Divide each side by 11 : x = -4
You're more than halfway there. Now you know what 'x' is,
and you can use it with either equation to find what 'y' is.
-- If you use it with the first equation: 2x + 3y = 1
Put in the value of 'x': 2(-4) + 3y = 1
Remove the parentheses: -8 + 3y = 1
Add 8 to each side: 3y = 9
Divide each side by 3 : y = 3
-- If you use it with the 2nd equation: y = 3x + 15
Put in the value of 'x' : y = 3(-4) + 15
Remove the parentheses: y = -12 + 15
Add numbers on the right side: y = 3 (same as the other way)
So there's your solution for the system of two equations:
x = -4
y = 3