A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. What is the final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature?A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.
B. A sample of 2.00 g of O2 is removed.
C. A sample of 4.00 g of O2 is added to the 4.80 g of O2 gas in the container.
Answers
Final answer:
By using the ideal gas law and molar mass calculations, the final volumes are found to be A. 65.0 L, B. 8.75 L, and C. 27.5 L.
Explanation:
To calculate the final volume when additional O2 is added or when some O2 is removed, we can use the concept of the molar mass and the ideal gas law that states that volume is directly proportional to the amount of gas, assuming pressure and temperature is constant.
The molar mass of O2 is approximately 32.00 g/mol.
A. 0.500 moles of O2 is added. This equals 0.500 * 32 g = 16 g. The total mass in the system is now 20.8 g. If the original 15.0 L represented 4.80 g, now 20.8 g would represent 15.0 L * 20.8/4.80 = 65.0 L.
B. 2.00 g of O2 is removed. So, the total mass in the system is now 2.80 g. If the original 15.0 L represented 4.80 g, now 2.80 g would represent 15.0 L * 2.80/4.80 = 8.75 L.
C. 4.00 g of O2 is added. So, the total mass in the system is now 8.80 g. If the original 15.0 L represented 4.80 g, now 8.80 g would represent 15.0 L * 8.80/4.80 = 27.5 L.
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When atoms react they form a chemical bond which is defined as a force of attraction that holds atom together. A force of attraction is defined as a kind of force that draws two or more objects together regardless of distance. There are two major categories of forces of attraction, one is intramolecular and intermolecular. Intramolecular forces is the presence of forces in atoms internally. While intermolecular is the force by which the force that is existent in two or more elements.
Final answer:
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Answers
1. 200.0 mL of 0.10 M iron (III) chloride = 0.2*0.1* 4 = 0.08
2. 800.mL of 0.10 M sucrose = 0.8 * 0.1 * 1 = 0.08
The two solutions have the same number of ions.
Answers
Answer:
The answer is c. 173 g
Explanation:
You know the reaction :
KClO3 ⇒ 2 KCl + 3 O2
By stoichiometry, that is, the amount of reagents and products in a chemical reaction when it is balanced (as in this case), it is known that for 2 moles of O2, 1 mole of KCLO3 is needed. So you can do the following rule of three to know the number of moles to produce 4.26 moles of 02:
If 1 mole of KClO3 is necessary to produce 3 moles of O2, how many moles are needed to produce 4.26 moles of 02?
So you need 1.42 moles of KClO3
Now it is necessary to know the molar mass of KClO3, which is the mass that contains 1 mole of the substance. For that you need to know the mass of K, Cl and O:
- K: 39 g/mol
- Cl: 35.45 g/mol
- O: 16 g/mol
So, the molar mass of KClO3 is:
39 g/mol + 35.45 g/mol + 3*16 g/mol=122.45 g/mol
because it contains 1 atom of K, 1 atom of Cl and 3 atoms of O.
Now, to calculate the mass representing 1.42 moles of KClO3 (needed to produce 4.26 moles of O2) you simply multiply that amount of moles by the molar mass:
This means that approximately 174 g of KClO3 are necessary to produce 4.26 moles of O2.
2KClO3 -> 2KCl + 3O2 (Always check if equation is balanced - in this case it is)
4.26moles
So we know that we have 4.26 moles of oxygen (O2). Now lets look at the ratio between KClO3 and O2.
We see that the ratio is 2:3 meaning that we need 2KClO3 in order to produce 3O2.
Therefore divide 4.26 by 3 and then multiply by 2.
4.26/3 = 1.42
1.42 * 2 = 2.84
Now we know that the molarity of KClO3 is 2.84 moles.
Multiply by R.M.M to find how many grams of KClO3 we have.
R.M.M of KClO3
K- 39
Cl- 35.5
3O- 3 * 16 -> 48
---------------------------
122.5
2.84 * 122.5 = 347.9 grams therefore the answer is (a)
348 grams needed of KClO3 to produce 4.26 moles of O2.
Hope this helps :).
Answers
-Physical condition: C₂H₅OH is liquid; CH₃OCH₃ is a gas.
-Reactivity: C₂H₅ reacts with sodium (Na) metallic, releasing H₂ and forming the sodium ethoxide, Na (+) C₂H₅-O (-) (C₂H₅ONa).CH₃OCH₃ no reacts with sodium.-water solubility: C₂H₅OH dissolves in any proportionCH₃OCH₃ is poorly soluble in H₂O.
-polarity: C₂H₅OH is very polar, form hydrogen bonds.CH₃OCH₃ is little polar, doesn't have H available to form hydrogen bridge.
Write C₂H₆O may cause ambiguity because there are 2 different substances with this formula:-ethyl alcohol or ethanol = CH₃---CH₂---H
methyl ether = CH₃---O---CH₃
If you label a bottle only with C₂H₆O, will be very difficult to know if the compound is methyl ether or ethanol, which can be very dangerous in the laboratory. As only the ethanol C₂H₅OH is structured, it is convenient to use preferably this formula. For the methyl ether, it is more efficient to use the formula CH₃OCH₃.
hope this helps!
Answers
Answer:
same number of protons as electrons
Explanation:
The addition of a neutron can make an atom radioactive. When you change the number of protons in an atom, you will change the atom from one element to a different element. ... If you change the number of electrons in an atom, you will get an ion of the element.