Which one is it ?? Please help
Answers
Answer:
its b.
Step-by-step explanation:
because.
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Thhhxxx
Find the value of t
Answers
Answer: t = 51
Step-by-step explanation:
Well hello buddy. How are you doing today? Might be a little bit bad because you have to deal with this weird triangle. BUT DONT WORRY DOG. I GOT YOU.
notice that that 112 number is on a straight line.... and straight lines are 180 degrees
With this in mind, lets subtract: 180 - 112 and we get= 68
ok so now we have these triangle angles: 68 and 61. also keep in mind that all angles of a triangle add up to 180
so 68 + 61 = 129
now do this: 180 - 129
the answer is 51
Answer:
51⁰
Step-by-step explanation:
there are 180⁰ on a straight line so if substrate 112⁰ from 180⁰ the answer will be 68⁰ so now we can get T simply like this below
61⁰+68⁰+T=180⁰
129⁰+T=180⁰
T=180⁰-129⁰
T=51⁰
Answers
Answer:
Step-by-step explanation:
7). 5.75% = =
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10). % =
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12). % =
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Now is you turn. You can do it!
a. 3,628,800
b. 1,814,400
c. 100
d. 0
Answers
Answers
Answer:
1 cause 4/8 is a half of the jug at it's full brethall
so one 1/2
Answer:
she can only get 1 servings
Answers
Answer:
80° because 50° 60° 70° and 80°
Answers
Answer:
The maximum volume of such box is 32m^3
V = x×y×z = 32 m^3
Step-by-step explanation:
Given;
Total surface area S = 48m^2
Volume of a rectangular box V = length×width×height
V = xyz ......1
Total surface area of a rectangular box without a lid is
S = xy + 2xz + 2yz = 48 .....2
To be able to maximize the volume, we need to reduce the number of variables.
Let assume the rectangular box has a square base,that means; length = width
x = y
Substituting y with x in equation 1 and 2;
V = x^2(z) ....3
x^2 + 4xz = 48 .....4
Making z the subject of formula in equation 4
4xz = 48 - x^2
z = (48 - x^2)/4x .......5
To be able to maximize V, we need to reduce the number of variables to 1, by substituting equation 5 into equation 3
V = x^2 × (48 - x^2)/4x
V = (48x - x^3)/4
differentiating V with respect to x;
V' = (48 - 3x^2)/4
At the maximum point V' = 0
V' = (48 - 3x^2)/4 = 0
Solving for x;
3x^2 = 48
x = √(48/3)
x = √(16)
x = 4
Since x = y
y = 4
From equation 5;
z = (48 - x^2)/4x
z = (48 - 4^2)/4(4)
z = 32/16
z = 2
The maximum volume can be derived by substituting x,y,z into equation 1;
V = xyz = 4×4×2 = 32 m^3