What time will it be 15 minutes later? Times:9:17 and 4:52 Please help good luck

Answers

Answer 1
Answer: 9:17 = 9:32
4:52 = 5:07
Answer 2
Answer: 9:32 and 5:07, all i did was add 15 to the minutes

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Samantha earns $18 per hour. How much will she earn if she works for 12 3/4 hours?

Answers

Answer:

She earned $229.50

Step-by-step explanation:

1 hr = $18

12.75 hrs = $18 × 12.75

= $229.50

$ 216
This is the answer

Y - 10 = 32.

Solve for x. Thanks Sooooo MUCH!! :-)

Answers

To solve this we will use inverse operations. 

The inverse operations for subtraction is addition.


y - 10 = 32

32 + 10 = 42

So, y = 42 BUT lets check our work.

42 - 10 = 32. 

So y = 42. 
y - 10 = 32

First, we have to make the variable (y) equal something. To do that, we have to do everything on one side of the problem. We can first start off by adding 10 to each side. This will make the variable equal the unknown answer.
y = 32 + 10

Second, we can now add 32 + 10. Once adding that, you will have the answer to the unknown variable. 32 + 10 = 42.
y = 42

Answer: \fbox {y = 42}

2/3 of the product of 3/8 and 16

Answers

finding the product of 2 numbers means that you have to multiply those numbers

(3)/(8) * 16

when multiplying fractions , numerators are multiplied by numerators and denominators by denominators

(3)/(8)*(16)/(1)  = (3*16)/(8*1) = (48)/(8) = 6

therefore product of 3/8 and 16 is 6

next we have to find 2/3 of 6

'of' operator means multiplication

(2)/(3) *(6)/(1) = (2*6)/(3*1) = (12)/(3) = 4


answer is 4

4

Further explanation

The Problem:

  • (2)/(3) of the product of (3)/(8) and 16.
  • Write an expression to match and then evaluate.

The Process:

Here are some early expressions that need attention.

  • two-thirds is (2)/(3)
  • three-eights is (3)/(8)
  • the product of (3)/(8) and 16 is (3)/(8) * 16

The term of "the product" is synonymous with multiplication.

Let us write an expression to match for (2)/(3) of the product of (3)/(8) and 16.

\boxed{\boxed{ \ (2)/(3) * \bigg( (3)/(8) * 16 \bigg ) \ }}

And now we evaluate the full expression.

\boxed{ \ = (2)/(3) * \bigg( (3)/(8) * 16 \bigg ) \ }

We can cross out 8 and 16.

\boxed{ \ = (2)/(3) * (3 * 2) \ }

\boxed{ \ = (2)/(3) * 6 \ }

We can cross out 3 and 6.

\boxed{ \ = 2 * 2 \ }

Thus, the result is 4.

- - - - - - - - - -

Quick Steps:

\boxed{ \ (2)/(3) * (3)/(8) * 16 \ }

\boxed{ \ (1)/(1) * (1)/(4) * 16 \ }

\boxed{ \ (16)/(4) \ or \ 16 / 4 \ }

\boxed{\boxed{ \ 4 \ }}

Learn more

  1. Write an expression to match for 15 times as much as 1 fifth of 12 and then evaluate brainly.com/question/2662877
  2. 7 copies of the sum of 8 fifths and 4 brainly.com/question/945784
  3. 4 times as much as 3 is brainly.com/question/573729

Keywords: 2/3, the product of 3/8 and 16, write an expression to match, and then evaluate, cross out, two-thirds, three-eights, synonymous with multiplication, the result, 4

The GDP is $1,465.2 billion. The population is 249,793,675. Find the per capita GDP.

Answers

Answer:

$5865.6 per capita.

Step-by-step explanation:

That is $1465,2 billion divided by 249,793,675

= 1,465,200,000,000 /  249,793,675

=  $5865.6 per capita.

Photo above. please help!

Answers

This is a proportion. You need to be able to find the missing value based on the information they've provided you with. 

Here's the best way to solve ⇒

2/3 = x/48
Cross multiply them.  ⇔   2*48 = 3x
96 = 3x
x = 32

the missing value is 32
Cross multiplication!
Because it is a proportion
(2)/(3)(?)/(48)
2 × 48 = 3 × ?
96 = 3 × ?
Divide by 3 on both sides to isolate the unknown number
(96)/(3)(3 * ?)/(3)
3 and 3 cancels out

32 = ?
The unknown number is 32

A graph with a line running through coordinates (0,0) and coordinates (30,24)Item 3

Carl's new car gets 27 miles per gallon. What is the equation that represents y, the total miles driven on x gallons of gas?


a. x = 27y

b. y = 27x

c. y = 27 + x

d. x = 27 + y

Answers

Answer:

b. y = 27x

Step-by-step explanation:

When you talk about "per" it means multiplication, and 27 is being multiplied by (x) gallons of gas.