Fourteen of the 100 digital video recorders​ (DVRs) in an inventory are known to be defective. What is the probability you randomly select an item that is not​ defective?

Answers

Answer 1
Answer:

What is the probability?

  • The probability is a measure of the likelihood of an event to occur.
  • P(A) is the probability of an event, n(A) is the number of favorable outcomes and n(S) is the total number of events in the sample space.
  • The probability that a randomly selected item is not defective is P(A) = n(A)/n(S).

We are given that a total of 100 digital video recorders​ (DVRs) out of these 14 are defective.

The probability of randomlyselect an item that is defective,

P(A) = n(A)/n(S)

P(A) = 14/100

P(A) = 7/50

The probability of randomlyselecting an item that is not defective,

P(A) = 1-(7/50)

P(A) = (50-7)/50

P(A) = 43/50

Hence, the probability of randomly selecting an item that is not​ defective is 43/50.

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Answer 2
Answer: P(non-defective) = 43/50
First, you subtract 14 from 100 to get the number of non-defective video recorders.
Then, you reduce the fraction of 86/100 to 43/50.

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What is the slope of the line 12x+4y=24?

Answers

12x+4y=24\ \ \ \ /-12x\n\n4y=-12x+24\ \ \ \ /:4\n\ny=(-12)/(4)x+(24)/(4)\n\ny=-3x+6\n\nAnswer:the\ slope\ is\ m=-3
12x+4y=24 \n \n the \ slope \ intercept \ form \ is : \n \n y= mx +b \n \n 4y =-12x+24 \ \ / :4 \n \ny=-(12)/(4)x+(24)/(6)\n \ny=-3x+ 4 \n \nAnswer : \ the \ slope \ m =-3

Write a equation of the line that passes through (-2,-3) and has a slope of 5

Answers

To get the Slope-Intercept form of a line, you first need to put it into Point-Slope form, which is y - y_1 = m (x - x_1) where x_1 and y_1 are the given coordinates and m is the given slope. So, plug your given information into the equation.

y + 3 = 5 (x + 2)   Use the Distributive Property
y + 3 = 5x + 10   Subtract 3 from both sides
      y = 5x + 7

Find the value of x when 6 - 3x = 5x - 10x + 10.

Answers

6 - 3x = 5x - 10x + 10

you’re answer would be :

x = 2

Answer:

x= 2

Step-by-step explanation:

Mr.lopez wrote the equation 32g+8g-10g=150

Answers

Answer:

g=5

Step-by-step explanation:

32g+8g-10g=150

30g=150

g=5

There were 480 people at play. The admission price was $2 for adults and $1 for children. The admission receipts were $770. How many adults and how many children attended?

Answers

Answer:

290 adults and 190 children attended the Play.

Step-by-step explanation:

Given:

Total number of people in play = 480

Let the number of adults be x

and Number of children be y

Hence we can write the equation as;

x+y=480 \ \ \ \ equation \ 1

Also Given:

Price for 1 adult = $2

Price for 1 children = $1

Total admission receipts = $770

Hence we can write the equation as;

2x+y =770 \ \ \ \ equation \ 2

Now We will subtract equation 1 from equation 2 we get;

(2x+y)- (x+y) =770-480\n2x+y-x-y= 290\nx= 290

Now substituting the value of x in equation 1 we get;

290+y =480\ny =480 -290\ny= 190

Hence 290 adults and 190 children attended the Play.

Final answer:

The problem is solved by creating two equations based on the given information and solving the system of equations to find that there were 290 adults and 190 children who attended the play.

Explanation:

To solve the problem of determining how many adults and children attended the play, we need to set up a system of equations.

Let A be the number of adults and C be the number of children who attended the play. We are given two pieces of information:
The total number of people at the play was 480, which gives us the equation A + C = 480.

The total amount of money collected from admissions was $770. Since adults pay $2 and children pay $1, the equation is 2A + C = 770.

Now we have a system of two equations:
A + C = 480

2A + C = 770

To solve this system, we can subtract the first equation from the second equation to eliminate C:

2A + C - (A + C) = 770 - 480

which simplifies to:

A = 290

Now, plug A = 290 into the first equation to find C:

290 + C = 480

Subtract 290 from both sides:

C = 190

So, there were 290 adults and 190 children at the play.

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What is the value of this expression when x = -5 and y = -3 (2)/(3) x^(3) y^(2)

Answers

Answer:

y = - 750

Step-by-step explanation:

Given

y = (2)/(3) x³y² ← substitute x = - 5, y = - 3 into the expression

  = (2)/(3) × (- 5)³ × (- 3)²

  = (2)/(3) × - 125 × 9 ( cancel the 3 and 9 )

  = 2 × - 125 × 3

  = - 750