Calculate the amount of energy released in the formation of one mole of BaSe bonds (not lattice energy). The radius of the barium ion is 1.35 Å, and the radius of the selenide ion is 1.98 Å. Note that 1Å=10−10m.
Answers
Final answer:
The lattice energy in the formation of one mole of BaSe bonds can be calculated using the equation Ulattice = (k * e2) / r, where k is the proportionality constant, e is the charge of the ions, and r is the distance between the ions. Given the radius of the barium ion and selenide ion, we can calculate the distance between them and then use it in the equation to find the lattice energy. The lattice energy in this case is approximately 10.8 billion N.
Explanation:
The amount of energy released in the formation of one mole of BaSe bonds can be calculated using the concept of lattice energy. Lattice energy is the energy released when ions come together to form a solid lattice structure. In this case, we have a barium ion (Ba2+) and a selenide ion (Se2-) coming together to form BaSe bonds.
To calculate the lattice energy, we can use the equation:
Ulattice = (k * e2) / r
Where:
- Ulattice is the lattice energy
- k is the proportionality constant (8.99 * 109 Nm2/C2)
- e is the charge of the ions (2 for Ba2+ and 2 for Se2-)
- r is the distance between the ions (which can be calculated using the sum of their radii)
Given that the radius of the barium ion is 1.35 Å and the radius of the selenide ion is 1.98 Å, we can calculate the distance between them and then use that value in the equation to find the lattice energy.
Let's calculate it:
Distance between ions = radius of Ba ion + radius of Se ion
= 1.35 Å + 1.98 Å
= 3.33 Å
Converting to meters:
= 3.33 * 10-10 m
Now, substituting the values in the equation:
Ulattice = (8.99 * 109 Nm2/C2) * (2 * 2) / (3.33 * 10-10 m)
= 10791849712.91 N
Therefore, the amount of energy released in the formation of one mole of BaSe bonds (lattice energy) is approximately 10.8 billion N.
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Answers
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