A camp ground consists of 12 square campsites arranged in a line along a beach. The distance from the edge of a campsite to the water at the end of the beach is 5 yards. The area of the campground, including the beach, is 1,248 square yards. What is the width of one campsite/

Answers

Answer 1
Answer: x=side length of a campsite
12x(5+x)=1248  because each campsite has a length of x and there are 12                           and from the top of the camp to the water is the 5 yds + a                             side length and LW=1248
60x+12x^2=1248
12x^2+60x-1248=0
x^2+5-14=0
(x+7)(x-2)=0
x+7=0 or x-2=0
x=-7 or x=2
x=2 because width can't be negative
the width of one campsite is 2 yds

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Solve for u. -24 = u ÷ 6
U=

Answers

Answer: Um, the answer is U= –144.

Step-by-step explanation:

Kevin claims he can draw a trapezoid with three right angles. Is this possible? Explain.

Answers

Using an indirect proof:

Assume that the figure is a trapezoid.
All trapezoids are quadrilaterals.
All quadrilaterals' interior angles add up to 360° because any n-gon's interior angles add up to 180(n-2)°.
We are given that the trapezoid has three right angles.
All right angles are 90°, thus these right angles have a total measure of 270°.
We can conclude fourth angle must be 90°.
If it has four right angles, it is a rectangle.
Rectangles have two sets of parallel sides.
However, trapezoids have exactly one set of parallel sides.
Alas, our figure cannot be a trapezoid.
not possibletrapezoid is a quadrilateral with 4 angles and 4 sideswhich means the interior measure =360if 3 angles are right the 4th angle must be a right anglea trapezoid does not have 4 right angles,it only has onepair of parallel sideshope this helps

| 3x | = 9
| -3r | = 9
b/5 = 1

Answers

|3x| = 9
|3x| = ±9
|3x| = 9    U    |3x| = -9
  3x = 9     U     3x = -9
   3     3              3      3
    x = 3               x = -3

|-3r| = 9
|-3r| = ±9
|-3r| = 9    U    |-3r| = -9
   3r = 9      U     3r = -9
    3    3               3     3
    r = 3                 r = -3

     ¹/₅b = 1
5(¹/₅b) = 5(1)
       b = 5

What is the equation of the following graph in vertex form?parabolic function going down from the left and turning at the point negative one comma zero and going up through the point zero comma one and continuing towards infinity
Courtesy of Texas Instruments

y = (x − 1)2
y = (x − 1)2 + 1
y = (x + 1)2 − 1
y = (x + 1)2

Answers

Correct answer is D.

Graph passes through the point (-1, 0).
Therefore, x = -1 and y = 0.

y=(x+1)^2\n0=(-1+1)^2\n0=0^2\n0=0 \;\; \text{T}

This is the only equation which is true for x = -1 and y = 0.
Therefore, the solution is y=(x+1)^2

Answer:

y = (x + 1)^2

Step-by-step explanation:

I used desmos and put each answer choice into the graphing calculator and answer choice D was the only one that matched with the image in the question.

What is the point in the middle of a circle called?A. Radius
B. Center
C. Circumference
D. Epicenter

Answers

The point in the middle of a circle called, B. Center

What are the circumference and diameter of a circle?

The circumference of a circle is the distance around the circle which is 2πr.

The diameter of a circle is the largest chord that passes through the center of a circle it is 2r.

We know, The largest chord that passes through the center of a circle is called a diameter.

All the other line segments that can be drawn with endpoints touching the circumference of a circle are called chords.

The radius is half the length of the largest chord(diameter).

A circle is defined as if we fix a point and mark points in a plane such that each point is equidistant from that fixed point a circle will be formed.

That fixed point is called the center of a circle.

learn more about circles here :

brainly.com/question/11833983

#SPJ7

Answer:

center

Step-by-step explanation:

How many circles have a center of (4,7)?

Answers

Any circle that can given by

(x-4)^(2)+(y-7)^(2)=r^(2)

have a center of (4,\;7).


You can choose any positive value for the radius r. Hence, there are infinity circles.