A 40-kg soccer player going through the air at 4m/s collides with a 60-kg player who is headed toward her at 3m/s, in the air. What is the speed and direction of the entangled players? Please explain how to do it
Answers
Answer: The entangled players would move with a speed of 0.2 m/s in the direction direction of the motion of second soccer player.
Explanation:
From law of conservation of momentum,
Initial momentum of the closed system = final momentum of the closed system
Since, no external force is acting on the players, total momentum would be conserved.
m₁u₁+m₂u₂=(m₁+m₂)v
where, m₁ is the mass of one soccer player = 40 kg
u₁ is its initial velocity before collision = 4 m/s
m₂ is the mass of the other soccer player = 60 kg
u₂ is the initial velocity before collision = - 3 m/s (∵opposite direction)
After collision, the two players get entangled and hence move with the same final velocity v.
40 kg × 4 m/s - 60 kg × 3 m/s = (40 kg + 60 kg ) v
160 kg m/s - 180 kg m/s = 100 kg v
v = -0.2 m/s
Hence, the entangled players would move with a speed of 0.2 m/s in the direction direction of the motion of second soccer player.
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Answers
Answer:
V = 20.5 m/s
Explanation:
Given,
The mass of the cart, m = 6 Kg
The initial speed of the cart, u = 4 m/s
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The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
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Hence, the wave speed will be 210 m/sec.
To learn more about the wavelength, refer to the link;
#SPJ2
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Explanation:
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