CHEMISTRY HIGH SCHOOL

Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is required to make 500.0 milliliters of a 6.0 M HCl?

Answers

Answer 1

Answer:

Answer : The volume of concentrated hydrochloric acid is, 0.25 liters

Explanation :

Using neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of concentrated hydrochloric acid = 12 M = 12 mole/L

$M_2$ = molarity of hydrochloric acid = 6 M = 6 mole/L

$V_1$ = volume of concentrated hydrochloric acid = ?

$V_2$ = volume of hydrochloric acid = 500 ml = 0.5 L

Now put all the given values in the above formula, we get the volume of concentrated hydrochloric acid.

$12mole/L* V_2=6mole/L* 0.5L$

$V_2=0.25L$

Therefore, the volume of concentrated hydrochloric acid is, 0.25 liters

Answer 2

Answer: M₁ *V₁ = M₂ * V₂

12.0 * V₁ = 6.0 * 500.0

12.0 V₁ = 3000

V₁ = 3000 / 12.0

V₁ = 250 mL

hope this helps!

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3. Rank each of the following in order of DECREASING atomic radius
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Answers

Answer:

Br,Ga,Cl?

Explanation:

Mintu wants to increase the heat transfer between a metal iron and another piece of metal he wants to shape. He decides to increase the time the two metals are in contact, use a larger metal iron, and use a new metal material with a higher specific heat. Where is Mintu's error?A:Mintu should have decreased the size of the metal iron
B:Mintu should have decreased the time he touches the two metals
C:Mintu should have chosen a material with a lower specific heat
D:Mintu should have chosen a material the same temperature as the iron.

Answers

Answer: Option (C) is the correct answer.

Explanation:

The amount of heat necessary to raise the temperature of 1 gram of a substance by $1^(o)C$ is known as specific heat of a substance.

Mathematically, q = $mC \Delta T$

where, q = Heat energy

C = specific heat

$\Delta T$ = change in temperature

Hence, smaller is the amount of heat required by a substance to raise the temperature of its 1 g by $1^(o)C$ more readily it will get hot.

Therefore, out of the given options specific heat of copper is small. So, copper will heat up quickly.

Thus, we can conclude that Mintu's error is that Mintu should have chosen a material with a lower specific heat.

Answer:

C - Mintu should have chosen a material with a lower specific heat.

Explanation:

0n edge 2020

Which balanced equation represents an oxidation-reduction reaction?(1) BaCl2 + Na2SO4==>BaSO4 + 2NaCl
(2) C+H2O ==>CO + H2
(3) CaCO3==>CaO + CO2
(4) Mg(OH)2 + 2HNO3==>Mg(NO3)2 + 2H2O

Answers

Correct Answer: option 2 i.e. (2) C+H2O ==>CO + H2

Reason:
Reaction is said to be oxidation-reduction (redox) type, when one species undergoes oxidation, while other species undergoes reduction. In present case, during the course of reaction, carbon is oxidized from '0' to '+2'. On other hand, hydrogen is reduced from '+1' to '0'.

The answer is (2). The oxidation-reduction reaction means that there is electrons transfer in the reaction. So there is valence change of at least two elements evolving in the reaction.

Formic acid, HCOOH, is a weak electrolyte what solutes are present in an aqueous solution of this compound write the chemical equation for the ionization of HCOOH

Answers

Answer:

Explanation:

Formic acid (HCOOH) is a weak electrolyte when dissolved in water. In an aqueous solution of formic acid, it partially ionizes into its constituent ions. The solutes present in this solution are the ions produced during ionization.

The chemical equation for the ionization of formic acid (HCOOH) in water is as follows:

HCOOH (aq) ⇌ H⁺ (aq) + HCOO⁻ (aq)

In this equation:

HCOOH represents formic acid molecules.

H⁺ represents the hydrogen ions (protons) that are formed when a molecule of formic acid loses a hydrogen ion (H⁺).

HCOO⁻ represents the formate ion, which is the conjugate base formed when a molecule of formic acid donates a hydrogen ion (H⁺).

Since formic acid only partially ionizes in water, not all molecules of formic acid dissociate into ions. This is why it is considered a weak electrolyte.

What is the percentage composition of CF4

Answers

The percentage composition of CF4 is %C = 13.64% and %F = 86.36%

The solution are as follows:
Molar mass of CF4 = 88
molar mass of C = 12
molar mass of F = 4x19 = 76

% C = 12/88 x 100 = 13.64%
% F = 76/88 x 100 = 86.36%

The percentage composition of compound CF₄ is %C = 13.64% and %F = 86.36% .

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:

1)Molecular compounds where in atoms are joined by covalent bonds.

2) ionic compounds where atoms are joined by ionic bond.

3)Inter-metallic compounds where atoms are held by metallic bonds

4) co-ordination complexes where atoms are held by co-ordinate bonds.

The solution are as follows:

Molar mass of CF₄ = 88

molar mass of C = 12

molar mass of F = 4 x 19 = 76

% C = 12/88 x 100 = 13.64%

% F = 76/88 x 100 = 86.36%

Learn more about compound,here:

brainly.com/question/14117795