A 500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car. The cars hook up and move off down the track together. How fast are they going? ( also how do I do it )

Answers

Answer 1
Answer:

Answer:

0.5ms^(-1)

Step-by-step explanation:

Let v be the speed after the collision of both the cars.

Now, momentum is given by: mass × velocity, then by equating the total momentum before and after the collision of the two cars, we get

500{*}0.8+300{*}0=(500+300)v

400+0=800v

400=800v

v=0.5ms^(-1)

Thus, they are moving at the velocity of 0.5ms^(-1)

Answer 2
Answer:

Answer:

0.5 m/s

Step-by-step explanation:

A 500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car.

Initial velocity of train, v_T=0.8\ m/s

Initial velocity of car, v_C=0\ m/s

Mass of train, m_T=500\ g

Mass of car, m_C=300\ g

The cars hook up and move off down the track together.

Let the final velocity of car and train, v_T=v_C=v

Using conservation of momentum,

Momentum before collision = Momentum after collision

m_T* v_T+m_C* v_C=(m_T+m_C)* v

500* 0.8+300* 0=(500+300)* v

v=(400)/(800)

v=0.5\ m/s

Hence, After collision they will going with 0.5 m/s


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Answers

Answer:

16= 8d-16-4

16= 8d-20

36=8d

d=4.5

Step-by-step explanation:

First you need to distribute the 2 to the numbers in the parenthesis.

Then you need to combine like terms

then add 20 to 36

then divide 36 by 8 to find d

Answer:

16= 8d-16-4

16= 8d-20

36=8d

d=4.5

Step-by-step explanation:

i just realised someone said this already...

Write words to match the expression 3+(4×12)

Answers

pemdas 
solve inside the parentheses first.
4 x 12 = 48
second add the products together
48 + 3 = 51

51 is the answer

How many time does 4 go into 52

Answers

13 times because 52 divided by 4 equals 13. Hope this helped!!

Need help to find x

Answers

Answer: x = 15

Step-by-step explanation: since ABCD is a parrallelogram, 9x-28 = 7x+2

if we solve that, we get x=15

The anwser is x = 15

A rectangular garden is 6 feet long and 4 feet wide. A second rectangular garden has dimensions that are double the dimensions of the first garden. What is the percent of change in perimeter from the first garden to the second garden?

Answers

double dimentions
perimiter

P=2(L+W)

if we have
L=6
W=4
P=2(6+4)
P=2(10)
P=20
original is 20
if both are doubled

6*2=12
4*2=8
P=2(12+8)
P=2(20)
P=40


from original to new is
from 20 to  40
what is percent  change?
find chnage
new-original=change
40-20=20
percent change=change/original
20/20=1=100%

answer is 100%
__________         _____________________
|    6 feet      |        |    6 feet       |     6 feet      |
|                   |        |                    |                    |    4 feet
|_________ |        |__________|__________|
                             |                    |                    |
                             |                    |                    |    4 feet
                             |__________|__________|

the figure shows that the second garden has a circumference twice . We must , however, prove.
Denote the sides of the first garden - a rectangle letters a and b
circuit garden
C
 = 2a + 2b = 2*(a+b)
The sides of the second garden also denoted with the letters a and b . We calculate the circuit
C₂ = 2*2a + 2*2b = 4a + 4b = 4*(a+b)

k = ( C_(2) )/( C_(1) ) = (4*(a+b))/(2*(a+b)) = (2*(a+b))/(1) = 2*(a+b)
 
2 = 2*100%=200%
200% -100% = 100%

Answer : The ratio of the second garden to the first ( ratio ) is 2 . Circuit increased by 100 %

A metric unit of measuring length that equal to 10 meters is called a

Answers

The metric unit of measuring length that is equal to 10 meters is called a decametre or a dekameter (depending on where you're from). It is a highly rarely used unit, but still exists.