what is required to bring about a phase change 1.an increase or decrease in pressure 2.an increase or decrease in energy 3.an increase in energy only 3.a decrease in energy only

Answers

Answer 1
Answer:

Answer: An increase or decrease in energy!

Explanation: I just took the quiz, I got it wrong with the increase or decrease of pressure. This is the right answer nowww.


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If the mass is doubled the kinetic energy will?

Answers

Besides the mass, kinetic energy also depends on speed.

If the speed remains constant, then kinetic energy is proportional
to mass. So if speed doesn't change while mass increases, then
kinetic energy increases, but I can't think of a situation where that
can happen.
it doubles, assuming the speed remains the same.

contrast the force of gravity between these pairs of objects: 1-kg mass and a 2-kg mass that are 1 m apart; a 1-kg mass and a 2-kg mass that are 2 m apart; and two 2=kg masses that are 1 m apart. helpppppp i dont understand.

Answers

force of gravitation between two different masses is given by

F = (Gm_1m_2)/(r^2)

here in first case we will have

F_1 = (G(1kg)(2kg))/((1m)^2)

F_1 = 2GNewton

another case we have

F_2 = (G(1kg)(2kg))/((2m)^2)

F_2 = (G)/(2)Newton

another case we have

F_3 =(G(2kg)(2kg))/((1m)^2)

F_3 = 4GNewton

so the force will be maximum in last case when two 2 kg mass is placed at 1 m distance and minimum force is in second case when 1kg and 2kg mass is placed at 2 m distance

What information does the atomic mass of an element provide? A. the sum of electrons and protons in an atom B. the difference between the number of protons and electrons C. the number of protons and neutrons in an atom D. the number of isotopes

Answers

C...

the atomic mass denotes the sum of the subatomic particles in a nucleus of an atom (neutron & proton).... the reason why the electron is not included is because it is very light and thus thought to be negligible.

What would change if the wave had higher frequency

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If the frequency of a wave increases and it stays in the same medium, then its wavelength decreases.

A weightlifter lifts a 1400 N barbell 2.5 meters. Calculate the work done during the lift

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Answer: W = 3500 J

Explanation: Work is the product of the amount of force and the perpendicular distance or W = Fd.

W = Fd

   = 1400 N ( 2.5 m )

   = 3500 J

Answer:

Force = 1400N

Displacement = 2.5 m

work done = F×D

=1400×2.5

= 3500 joule

A shopper pushes a 7.32 kg grocery cartwith a 14.7 N force directed at
-32.7° below the horizontal.
What is the normal force on the cart?​

Answers

Answer:

The "normal force" on the "cart" 63.893 N.

Explanation:

To find normal force on the cart, use the equation

Normal force  = mg + F sinx,  

“m” being the object's mass,  

“g” being the acceleration of gravity,

“x” being the angle of the cart

Given values

M = 7.33 kg

F = 14.7 N

x=-32.7^(\circ)

\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^(2) \text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^(2) \text { on Earth }

Substitute the values in above equation

Normal force = (7.33 × 9.8) + 14.7 sin(-32.7°)

Normal force = 71.834 + 14.7 × (-0.5402)

Normal force = 71.834 - 7.94094

Normal force = 63.893 N

The "normal force" on "the cart" 63.893 N.

The normal force on the cart is 79.7 N

Explanation:

In order to find the normal force, we have to analyze the forces acting on the cart on the vertical direction.

In the vertical direction, we have the following forces:

The weight of the cart, downward, of magnitude , where m is the mass of the cart and g is the acceleration of gravity

The normal force on the cart, upward, we indicate it with N

The component of the pushing force acting in the vertical direction, downward, of magnitude , where F is the magnitude of the force and is the angle of the force with the horizontal

Therefore, the equation of the forces on the cart in the vertical direction is:

where the net force is zero since the cart is balanced in the vertical direction. We have:

We take the angle as positive since we are already considering the downward direction in the equation.

Substituting and solving for N, we find the normal force:

Learn more about forces:

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