A motorist driving at 25 meters/second decelerates to 15 meters/second. The combined mass of the vehicle and the driver is 1.5 × 10³ kilograms. What is the amount of mechanical work done by the vehicle?

Answers

Answer 1
Answer: Kinetic energy = (1/2) (mass) (speed)²

Before slowing down, the car's speed is 25 m/s,
and its kinetic energy is ...

                             (1/2) (1,500 kg) (25 m/s)²

                          = (1/2) (1,500 kg) (625 m²/s²)

                          =        468,750 joules .

After slowing down, the car's speed is 15 m/s,
and its kinetic energy is ...

                             (1/2) (1,500 kg) (15 m/s)²

                          = (1/2) (1,500 kg) (225 m²/s²)

                          =         168,750 joules.

The car lost  (468,750 - 168,750) = 300,000 joules of K.E. 

The law of Conservation of Energy says:

                  That 300,000 joules had to go somewhere.

If it's a standard, gas-powered car, then the kinetic energy got
put into the brakes.  The energy turned into heat, and the heat
was carried off in the air.

If it's a more modern electric or hybrid car, then the kinetic energy
spun the wheel motors, turning them temporarily into electrical
generators.  The generators converted the kinetic energy into
electrical energy, which got put back into the car's batteries, and
could be used again.  That's why electric cars use less gas. 
Answer 2
Answer:

Answer:

Kinetic energy = (1/2) (mass) (speed)²

Before slowing down, the car's speed is 25 m/s,

and its kinetic energy is ...

                            (1/2) (1,500 kg) (25 m/s)²

                         = (1/2) (1,500 kg) (625 m²/s²)

                         =        468,750 joules .

After slowing down, the car's speed is 15 m/s,

                            (1/2) (1,500 kg) (15 m/s)²

                         = (1/2) (1,500 kg) (225 m²/s²)

                         =         168,750 joules.

The car lost  (468,750 - 168,750) = 300,000 joules

and you heard it from the  KING


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A pillow is thrown downward with an initial speed of 6 m/s.After 4 seconds, the pillow's velocity is m/s. (g= -9.8m/s2)

Answers

The velocity of the pillow after 4 seconds is -45.2 m/sec and this can be determined by using the velocity formula.

Given :

A pillow is thrown downward with an initial speed of 6 m/s.

The equation of velocity is used in order to determine the pillow's velocity after 4 seconds.

v = u + at

where 'v' is the final velocity, 'a' is the acceleration due to gravity, 'u' is the initial velocity, and 't' is the time.

Now, substitute the known terms in the above equation in order to determine the pillow's velocity after 4 seconds.

v = -6 - 9.8 * (4)

Simplify the above equation.

v = -6 - 39.2

v = -45.2 m/sec

So, the velocity of the pillow after 4 seconds is -45.2 m/sec.

For more information, refer to the link given below:

brainly.com/question/13639113

Given :

Initial velocity, u = -6 m/s.

Time taken, t = 4 seconds.

Acceleration due to gravity, g = -9.8\ m/s^2.( Here negative sign means downward direction )

To Find :

Velocity after 4 seconds.

Solution :

By equation of motion.

v = u + at

Here , a = g.

v = u + gt

v = -6 + (-9.8)×4

v = -6 + (-39.2)

v = -45.2 m/s

Therefore, velocity after 4 seconds is -45.2 m/s.

Hence, this is the required solution.

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Answers

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Answers

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