MATHEMATICS MIDDLE SCHOOL

Find the supplement to each angle of 100°

Answers

Answer 1

Answer: Whalers is the picture to the supplementary angle 100°

Answer 2

Answer:

Answer:

80⁰

Step-by-step explanation:

Angle = 100⁰

Supplement = 180 - 100 = 80⁰

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Please help i have know idea what to do please help and show work so i can understand thank you!1.) k+3/4k-2 * (12k^2-3)
2.) x^2-16/6x * 7x/x+5
3.) q+5/2 * 4q/q+4
4.)y^2-9/-2y * -5y/y+3
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6.)(8x^3-30+21) divided by (4x-6)
7.)(-10m^9-4m-12m^6) divided by 2m^4

Answers

1. $(k + 3)/(4k - 2)(12k^(2) - 3})$
$(k + 3)/(2(2k) - 2(1))(3(4k^(2)) - 3(1))$
$(k + 3)/(2(2k - 1))(3(4k^(2) - 1))$
$(k + 2)/(2(2k - 1))(3(4k^(2) + 2k - 2k - 1))$
$(k + 3)/(2(2k - 1))(3(2k(2k) + 2k(1) - 1(2k) - 1(1))$
$(k + 3)/(2(2k - 1))(3(2k + 1) - 1(2k + 1))$
$(k + 3)/(2(2k - 1))(3(2k - 1)(2k + 1))$
$(3(k + 3)(2k + 1))/(2)$

2. $((x^(2) - 16)/(6x))((7x)/(x + 5))$
$((x^(2) + 4x - 4x - 16)/(6))((7)/(x + 5))$
$((x(x) + x(4) - 4(x) - 4(4))/(6))((7)/(x + 5))$
$((x(x + 4) - 4(x + 4))/(6))((7)/(x + 5))$
$(((x - 4)(x + 4))/(6))((7)/(x + 5))$
$(7(x - 4)(x + 4))/(6(x + 5))$

3. $((q + 5)/(2))((4q)/(q + 4))$
$((q + 5)/(1))((2q)/(q + 4))$
$(2q(q + 5))/(q + 4)$

4. $((y^(2) - 9)/(-2y))((-5y)/(y + 3))$
$((y^(2) + 3y - 3y - 9)/(2))((5)/(y + 3))$
$((y(y) + y(3) - 3(y) - 3(3))/(2))((5)/(y + 3))$
$((y(y + 3) - 3(y + 3))/(2))((5)/(y + 3))$
$(((y - 3)(y + 3))/(2))((5)/(y + 3))$
$((y - 3)/(2))((5)/(1))$
$(5(y - 3))/(2)$

5. $(8x^(2) - 20x + 15)/(2x - 3)$

6. $(8x^(3) - 30 + 21)/(4x - 6)$
$(8x^(3) - 9)/(2(2x) - 2(3))$
$(8x^(3) - 9)/(2(2x - 3))$

7. $(-10m^(9) - 12m^(6) - 4m)/(2m^(4))$
$(-10m^(9))/(2m^(4)) - (12m^(6))/(2m^(4)) - (4m)/(2m^(4))$
$-5m^(5) - 6m^(2) - (2)/(m^(3))$

The measure of an angle is fourteen times the measure of a s

Answers

The total measure is 98.

12 is what percent of 96 in an equation

Answers

96/x=100/12
(96/x)*x=(100/12)*x - we multiply both sides of the equation by x
96=8.33333333333*x - we divide both sides of the equation by (8.33333333333) to get x
96/8.33333333333=x
11.52=x
x=11.52

8) Write the equation of a line that is parallel to y = 2x + 3 and passes through the points (0,4)

Answers

Answer:

y = 2x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x + 3 ← is in slope- intercept form

with slope m = 2

Parallel lines have equal slopes, thus

y = 2x + c ← is the partial equation

Note this line passes through (0, 4) ⇒ c = 4

y = 2x + 4 ← equation of parallel line

Write 63 as a sum of tens and ones

Answers

The sum of 6+3 (63) = 9.

Explain why 2 x 3/8 is equivalent to 2 x 3 x 1/8 ?

Answers

If you put the 2 over 1 in 2 x 3/8 and multiply cross like normal fractions, you will get 6/8. This reduces to 3/4. Similarly, if you multiply 2 x 3, you get 6. Put the 6 over 1 and multiply by 1/8 to get 6/8 as an answer which reduces to 3/4 as well.

2x + 3 = 8

Transpose 3

2x + 3 - 3 = 8 - 3

2x = 5

Divide both sides of the equation by 2

2x / 2 = 5 / 2

x = 5 / 2

x = 2 1/2

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