How to do improper fractions with 3.8 repeating

Answers

Answer 1

Answer: 3.88888=3.88888/1=38.8888888

so lets ssay our repeating decimal = a fraction x
x=3.888 is true
multiply by 10
10x=38.8888
now subtract fir frist eqation from second
10x-x=38.8888-3.888888
9x=35
divide both sides by 9
x=35/9
x=3 and 7/9

anser is 3.88=3 and 7/9

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51. Q(3, 9), P(-1,5)
find the coordinates of the missing endpoint if P is the midpoint of NQ

Answers

X1= 3, Y1= 9
Midpoint formula= (?,?)= (x1+x2/2 , y1+y2/2)
-2= 3+? Making ?= -5
10= 9+? Making ?= 1
So your answer is (-5,1)= N

Final answer:

The coordinates of the missing endpoint, if P is the midpoint of segment NQ, are found using the formula N = 2P - Q. Substituting the given values into this formula, the coordinates of the missing point N are (-5, 1).

Explanation:

If point P is the midpoint of segment NQ, we can use the formula for finding the coordinates of the endpoint if we know the midpoint and one endpoint. The formula states:

To find the missing endpoint (in this case, point N), we use the formula: N = 2P - Q

Substituting the given values into the formula, we get:

N = 2(-1, 5) - (3, 9)

N = (-2, 10) - (3, 9)

N = (-5, 1)

So, the coordinates of the missing endpoint N are (-5, 1).

Learn more about Midpoint Formula here:

brainly.com/question/15085041

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How can I get the area of the shaded region?

Answers

Let's work on the triangle first. The x intercept of 2y=27-3x is

0 = 27 - 3x

3x = 27

x = 9

So A(9,0)

B is the meet of 2y=27-3x and y=3x

2y=27-y

3y=27

y=9

y is the height of OAB; we don't really need x

Area(OAB) = $\frac 1 2 (9)(9) = (81)/(2) = 40.5$

Now we have to subtract

$\displaystyle \int_0^9 (3x - x^(\frac 3 2))dx = \frac 3 2 x^2 - \frac 2 5 x^(\frac 5 2) \bigg|_0^9 = \frac 3 2 (9^2) - \frac 2 5 (9^(\frac 5 2)) = (1)/(2)(243) - \frac 2 5 (243) = 24.3$