Why can water dissolve many ionic compounds

Answer is: heat conductivity.

Thermal conductuction is the transfer of heat through physical contact. Thermal conduction is the transfer of heat by microscopic collisions of particles. Heat spontaneously flows from a hotter to a colder body.

The process of heat conduction depends on four basic factors: the temperature gradient, the cross section of the materials involved, their path length and the properties of those materials.

Metallic bond increace electrical and thermal conductivity.  

Metals conduct heat, because when free moving electrons gain energy (heat) they vibrate more quickly and can move around.  

The equation is not balanced because the number of atoms of Oxygen present in the reactants and product sides are not equal

The equation being referred to in the question can be written properly as

S + 3O₂ → SO₃

To determine whether the equation is balanced or not

We will check if the coefficient in the equation gives equal numbers of atoms for each element in the reactants and product

• For the reactants side

S = 1

O = 6

• For the product side

S = 1

O = 3

We can observe that, the coefficient does not give equal number of atoms for the element, Oxygen (O), in the reactants and product sides

∴ The equation is NOT balanced

Hence, the equation is not balanced because the number of atoms of Oxygen present in the reactants and product sides are not equal

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Answer:

This equation is not balanced because you don't have the same amount of each element on each side of the chemical reaction. The balanced equation is:

2 S + 3 ⇒ 2

Explanation:

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.  

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Then, taking into account all of the above, you can determine the amount of elements on each side of the equation:

Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by sub-index 2)

Right side: 1 sulfur S and 3 oxygen O (subindice value)

As you can see, you have the same amount of sulfur on both sides of the equation but the amount of oxygen is different. This indicates that the chemical equation is not balanced. To balance it, as the amount of sulfur is the same, the amount of oxygen must be balanced, which is different on each side of the reaction.

A simple way is to balance the equation is to multiply the product by 2, that is, add a coefficient 2 in front of the SO3 molecule, the reaction being as follows:

S + 3 ⇒ 2

Now the amount of elements on each side of the equation is:

Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)

Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)

The oxygen is now balanced, but the amount of sulfur on both sides of the reaction varies. To balance the quantities of sulfur, as now on the right side you have an amount of 2, you can add the coefficient to sulfur. The chemical equation is as follows:

2 S + 3 ⇒ 2

Now the amount of elements on each side of the equation is:

Left side: 2 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)

Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)

Finally you have the same amount of sulfur and oxygen on both sides of the reaction. So the chemical equation is finally balanced.

Answer:

N2 Covalent

CCl4 Covalent

SiO2 Covalent

AlCl3 Covalent

CaCl2 Ionic

LiBr Covalent

Explanation:

With covalent bonds, there is a sharing of electron pairs between the atoms.

With ionic bonds, there is complete transfer of valence electrons between atoms. Formed by the interaction of a metal with a non-metal.

Where:

Electrons aren't transferred in covalent bonds.

Protons aren't  transferred in covalent bonds

Protons aren't shared in covalent bonds

N3-

C4+

Cl-

Si4+ = Metal

O2- = Non-metal

Al3+ = Metal

Li+ = Metal

Ca2+ = Metal

Br  1-, 1+, 5+ = Halogen

N2 = N3- and N3- Covalent

CCl4 = C4+ and Cl- x4 Covalent

SiO2 = Si4+ and O2- x 2 Metal with non metal Covalent

AlCl3 = Al3+ and Cl- x 3 Covalent Though this one is complex as to why because it seems like it should be ionic

CaCl2 = Ca2+ and Cl- x 2 Metal with non-metal Ionic

LiBr = Li+ and Br- Covalent as neither is a non-metal

Answer:

A - actinide-series element  

Explanation:

If you go to the periodic table, the atomic number is 92. if you look for 92 you will end up in the inner transition metals then if you get more detail it would be in the actinide section.

The most specific classification for the element uranium is option a, it is an actinide series element. It is a radioactive element.

What is uranium?

Uranium is 92nd element in periodic table. This is a f- block element. In periodic table the elements of groups 3-12 is called transition metals. Elements in f block is called inner transition elements.

The inner transition elements contain two classification, lanthanides and actinides. 57th to 71th elements are called lanthanides. 89 to 103 are called actinides.

Thus, uranium belongs to the actinide series of  f block elements in the periodic table therefore, option a is correct.

To learn more about actinides, refer the link below:

brainly.com/question/5188867

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An occluded front forms when a warm air mass is caught between two cooler air masses.