Given the reaction: 4Al(s)+3O2(g)==2Al2O3(s) What is the minimum number of grams of oxygen gas required to produce 1.00 mole of aluminum oxide
Answers
3 moles O₂ -------------> 2 moles Al₂O₃
? moles O₂ --------------> 1.00 mole Al₂O3
O₂ = 1.00 * 3 / 2
O₂ = 3 / 2
= 1.5 moles of O₂
Molar mass O₂ = 32.0 g
1.5 * 32.0 = 48 g of O₂
hope this helps!
Grams of the gas can be estimated by multiplying the moles and the molar mass. To produce 1 mole of aluminum oxide, 48 gms of oxygen is required.
What is mass?
The mass of the substance is the product of the moles and the molar mass of the given substance.
The balanced chemical reaction is shown as:
4 Al (s) +3 O₂ (g) → 2 Al₂O₃ (s)
From the above reaction, it can be concluded that:
3 moles of oxygen = 2 moles of aluminum oxide
So, x moles of oxygen = 1.00 moles of aluminum oxide
x is calculated as:
x = 3 ÷ 2 = 1.5 moles
Mass of oxygen:
mass = moles × molar mass
= 1.5 × 32
= 48 gms
Therefore, 48 gms of oxygen is required to produce 1 mole of aluminum oxide.
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Write the balanced equation for the reaction given below: C2H6 + O2 --> CO2 + H2O. If 16.4 L of C2H6 reacts with 0.980 mol of O2, how many liters of carbon dioxide gas will be produced? What is the limiting reagent? How many oxygen atoms will be in this sample of carbon dioxide? How many moles of the excess reactant will be left over? How many grams of the excess reactant will be left over?
What determines the strength of a dipole-dipole force?A. The more symmetrical the molecule, the stronger the force.B. The more hydrogen in the molecule, the stronger the force.C. The more polar the molecules, the stronger the force.D. The larger the atomic radius, the stronger the force.
Electronegativity is a measure of an atoms ability to
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B. Why does density increase as you move from the crust to the core?
C. Why does density decrease as you move from the crust to the core?
D. Why is the inner core liquid iron and the outer core solid iron?
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Answer:
The answer is C
Explanation:
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Molarity NaOH = 0.1 M
Number of moles NaOH :
n = M * v
n = 0.1 * 0.054
n = 0.0054 moles of NaOH
Finally we calculate the number of moles of HCl in the solution from the stoichiometry of the reaction :
HCl + NaOH = NaCl + H₂O
1 mole HCl -------- 1 mole NaOH
? moles HCl ------- 0.0054 moles NaOH
moles HCl = 0.0054 * 1 /1
= 0.0054 moles of HCl
Volume of HCl = 125 mL / 1000 = 0.125 L
M ( HCl ) = n / V
M = 0.0054 / 0.125
= 0.0432 M
hope this helps!
Answers
NH₃ = 17.031 g/mol
hope this helps!
Answers
Answer:
The Carnot engine operates based on the principles of the Carnot cycle, which is a theoretical idealized thermodynamic cycle. To calculate the work done by the engine, we need to use the formula for the efficiency of the Carnot cycle.
The efficiency of a Carnot engine is given by the equation:
Efficiency = 1 - (T2 / T1),
where T2 is the exhaust temperature in Kelvin and T1 is the burn temperature in Kelvin.
First, we need to convert the temperatures from Celsius to Kelvin.
The burn temperature is 1957 ˚C, so we add 273 to convert it to Kelvin:
T1 = 1957 + 273 = 2230 K.
The exhaust temperature is 500 ˚C, so we add 273 to convert it to Kelvin:
T2 = 500 + 273 = 773 K.
Now we can calculate the efficiency:
Efficiency = 1 - (T2 / T1) = 1 - (773 / 2230).
Next, we need to calculate the heat input, which is the energy released by burning 1 kg of methane.
The energy released by burning methane can be calculated using the heat of combustion of methane, which is -891 kJ/mol.
To convert this to joules per kilogram, we need to know the molar mass of methane, which is 16 g/mol.
1 kg of methane is equal to 1000 g, so the number of moles of methane in 1 kg is:
1000 g / 16 g/mol = 62.5 mol.
The heat released by burning 1 kg of methane is:
-891 kJ/mol * 62.5 mol = -55,687.5 kJ.
To convert this to joules, we multiply by 1000:
-55,687.5 kJ * 1000 = -55,687,500 J.
Now we can calculate the work done by the engine:
Work = Efficiency * Heat input.
Substituting the values we calculated:
Work = (1 - (773 / 2230)) * (-55,687,500 J).
Finally, we can calculate the work done by the engine in joules.
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Answer:
Average speed of the racer is 5.8 m/s.
Explanation:
Total distance covered by racer = D = 406 m
Total time taken racer= T = 70 seconds
The formula of an average speed is given by:
Average speed :
Average speed of the racer is:
5.8 m/s=406/70
1km = 100m
1h= 3600s
(5.8m/s)(1km/100m)(3600s/1h)