The following balanced equation shows the formation of sulfur dioxide. S + O2 mc023-1.jpg SO2 How many moles of sulfur are needed to produce 15.0 mol of sulfur dioxide?

Answers

Answer 1
Answer:

For the given chemical reaction, 15 moles of sulfur are required to produce 15 moles of sulfur dioxide.

What is the balanced chemical equation?

A chemical equation can be defined as a representation of a chemical reaction in the form of symbols of the substances. A chemical equation consists of contributing reactants in the reaction, formed products, and their physical states.

The chemical equation in which the number of atoms of each element is equal on both sides of the equation is called a balanced chemical equation.

The law of conservation of mass follows by a balancing of a chemical equation therefore, the total mass of the elements on the reactant side must be equal to the total mass of elements on the product side.

Given, the chemical equation is:  S + O₂ → SO₂

From the above equation, we can say that one mole of sulfur produces one mole of sulfur dioxide.

Given the moles of the sulfur dioxide = 15 moles

The moles of sulfur required to make 15 moles of sulfur = 15 moles

Therefore, 15 moles of sulfur are required for the given conditions.

Learn more about the balanced chemical equation, here:

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Answer 2
Answer: S + O₂ = SO₂

1 mole S ------------ 1 mole SO₂
? mole S ----------- 15.0 mole SO₂

S = 15.0 * 1 / 1

= 15 moles of S

hope this helps!

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Consider the dissolution of 2.50 grams of salt XY in 75.0 mL of water within a calorimeter. The temperature of the water decreased by 0.93 oC. The heat capacity of the calorimeter is 42.2 J/oC. The density of the water (and the solution) is 1.00 g/mL. The specific heat capacity of the solution is 4.184 J/goC. Calculate the enthalpy change for dissolving this salt on a energy per mass basis (units of J/g).

Answers

The enthalpy change for dissolving this salt on a energy per mass is 136.32 J/g

How to determine the mass of the water

  • Density of water = 1 g/mL
  • Volume of water = 75 mL
  • Mass of water =?

Mass = Density × Volume

Mass of water = 1 × 75

Mass of water = 75 g

How to determine the heat absorbed by the solution

  • Mass of water = 75 g
  • Mass of salt =  2.50 g
  • Mass of solution (M) = 75 + 2.5 = 77.5 g
  • Temperature change (ΔT) = 0.93 °C
  • Specific heat capacity of the solution = 4.184 J/gºC
  • Heat of solution (Q) =?

Q = MCΔT

Q = 77.5 × 4.184 × 0.93

Q = 301.5618 J

How to determine the heat consumed by the calorimeter

  • Heat capacity of the calorimeter (C) = 42.2 J/ºC
  • Temperature change (ΔT) = 0.93 °C
  • Heat by calorimeter (H) =?

H = CΔT

H = 42.2 × 0.93

H = 39.246 J

How to determine the total heat released

  • Heat of solution (Q) = 301.5618 J
  • Heat by calorimeter (H) = 39.246 J
  • Total heat =?

Total heat = 301.5618 + 39.246

Total heat = 340.8078 J

How to determine the enthalpy change

  • Total heat = 340.8078 J
  • Mass of salt = 2.5 g
  • Enthalpy change (ΔH) =?

ΔH = Total heat / mass

ΔH = 340.8078 / 2.5

ΔH = 136.32 J/g

Learn more about heat transfer:

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Answer : The enthalpy change for dissolving this salt on a energy per mass basis is 132.4 J/g

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1* \Delta T+m_2* c_2* \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the water

c_1 = specific heat of calorimeter = 42.2J/^oC

c_2 = specific heat of water = 4.184J/g^oC

m_2 = mass of water = Density* Volume=1/mL* 75.0mL=75.0g

\Delta T = change in temperature = 0.93^oC

Now put all the given values in the above formula, we get:

q=[(42.2J/^oC* 0.93^oC)+(75.0g* 4.184J/g^oC* 0.93^oC)]

q=331.08J

Now we have to calculate the enthalpy change for dissolving this salt on a energy per mass basis.

\Delta H=(q)/(m)

where,

\Delta H = enthalpy change = ?

q = heat released = 331.08 J

m = mass of salt = 2.50 g

\Delta H=(331.08J)/(2.50g)=132.4J/g

Therefore, the enthalpy change for dissolving this salt on a energy per mass basis is 132.4 J/g

1) This method is a technique used in separating a less-dense substance from a denser one. A. Evaporation. B. Decantation. C. Picking. D. All of the above. 2) What will happen to the less-dense substance of mixtures if you separate them using decantation method? A. Remain the same. B. It will become solid. C. It will evaporate. D. It will float up. 3) In the process of decantation, the mixture is left: A. Behind. B. Undisturbed. C. Removed. D. None of the above. 4) How can the decantation method be useful in everyday life? A. It helps us to become more productive. B. It gives us satisfaction in our everyday living. C. It's just an ordinary technique. D. It helps us to make our everyday living more efficient and easier.

Answers

Answer:

1. B Decantation. 2. D 3. B

Explanation:

This method is often used when dealing with mixtures of liquids or immiscible liquids with different densities

2. This is because the denser substance sinks to the bottom due to its higher density, while the less dense substance remains on the surface. It allows for the separation of the two substances based on their density.

3. The mixture is left undisturbed after the less dense substance has been poured off. This allows the denser substance to settle at the bottom while the lighter substance remains on top

4. It's a handy method for separating substances based on their density For example, if you have a mixture of oil and water, you can use decantation to separate the two. By letting the mixture sit undisturbed, the oil, being less dense, will float to the top, allowing you to carefully pour it off and separate it from the water.

Which of the following combinations will result in a reaction that is spontaneous at all temperatures?positive enthalpy change and positive entropy change
positive enthalpy change and negative entropy change
negative enthalpy change and positive entropy change
negative enthalpy change and negative entropy change

Answers

The right answer for the question that is being asked and shown above is that: "negative enthalpy change and negative entropy change." The combination that will result in a reaction that is spontaneous at all temperatures is negative enthalpy change and negative entropy change

Answer:

Spontaneous at ALL Temperatures: Negative enthalpy change and positive entropy change

I promise this is 100% correct. I just took the Honors Entropy quiz and I got the question correct.

The other answer provided by the verified user Hagrid is incorrect.

Is the compound CO ionic or covalent

Answers

If a compound is made of one metal and one non-metal it's bond will be ionic, whereas if a compound is made of two non-metals, it's bond will be covalent. 

C - Non-Metal
O - Non-Metal

CO = Covalent.

Which of the following is an example of a molecule? (A) CO₂ (carbon dioxide). (B) H₂O (water). (C) O₂ (oxygen in atmosphere). (D) NaCI (sodium chloride:table salt). ?

Answers

my best guess is d ... 

Which diatomic molecule is formed when thetwo atoms share six electrons?
(1) H2
(2) N2
(3) O2
(4) F2

Answers

Answer: (2) N_2

Explanation:

1) H_2 is a diatomic molecule which is formed by sharing of two electrons between two hydrogen atoms.

2)  N_2 is a diatomic molecule which is formed by sharing of six electrons between two nitrogen atoms.

3) O_2 is a diatomic molecule which is formed by sharing of four electrons between two oxygen atoms.

4) F_2 is a diatomic molecule which is formed by sharing of two electrons between two fluorine atoms.


I believe the correct answer from the choices listed above is option 2. The diatomic molecule that is formed when the
two atoms share six electrons would be N2. 
It has five valence electrons, so it needs three more valence electrons to complete its octet.