On a temperature versus time graph, how does the temperature at the beginning of a change of state compare with the temperature at the end of the change?

Answers

Answer 1
Answer:

the answer is ALWAYS THE SAME.

Answer 2
Answer:

Answer:B

Explanation:


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A single atom of an element has 11 protons, 11 electrons, and 12 neutrons. Which element is it?

Answers

I think the answer is sodium 

Final answer:

The element with 11 protons, 11 electrons, and 12 neutrons is an Isotope of Sodium, specifically Sodium-23. The atomic number, determined by the number of protons, identifies the element.

Explanation:

The element described here, with 11 protons, 11 electrons, and 12 neutrons, is Sodium. The number of protons in an atom defines the atomic number, and thus identifies the element. In this case, the atomic number is 11, which corresponds to Sodium on the periodic table. Neutrons contribute to the mass number, but not the identity of the element. Therefore, an element with 11 protons and 12 neutrons is an isotope of Sodium. Sodium normally has 11 neutrons, but in this case, it has 12, which makes it an isotope of Sodium commonly referred to as Sodium-23.

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Stalactites and stalagmites are examples of _____.organic sedimentary rock
contact metamorphism
extrusive igneous rock
chemical sedimentary rock

Answers

The right option is; chemical sedimentary rock

Chemical sedimentary rocks are rocks that are formed by precipitation of minerals from water. Chemical sedimentary rocks are also called evaporates and they are usually composed of the minerals halite (calcium chloride) and gypsum (calcium sulfate). Examples of chemical sedimentary rocks include stalactites, stalagmites, rock salt, flint, and some dolomites.

Answer:

The correct answer is option D, chemical sedimentary rock

Explanation:

Both stalactites and stalagmites are called drip stone as they are formed of the dripping water consisting of minerals. Both stalactites and stalagmites hang up from the ceiling of caves. These are also refereed to as Chemical sedimentary rocks formed by precipitation. The three major processes involved in the formation of these two rocks are –  

a) Physical weathering – which disintegrates the minerals contained in the igneous, sedimentary, or metamorphic rock

b) Chemical weathering – which involves dissolution of weathered rock minerals

c) Precipitation of the dissolved minerals.  

The density of a liquid form of a material is always less than the density of the solid form of that same material true or false

Answers

Answer:

False

Explanation:

This property depends on the intermolecular interactions of the analyzed compound.

In most cases, this property is fulfilled, but one of the most important exceptions is water since ice cubes float in liquid water which means that its density is lower than that of liquid water.

This is due to one of the types of bonds that binds hydrogen bonds to water molecules.

Hydrogen bridges are a molecular interaction that occurs between the hydrogen in one molecule of water and the oxygen in another molecule.

Recall the formula of the density

d=(m)/(v)

The volume is inversely proportional to the density this means that the lower the volume the higher the density and the higher the volume the lower the density.

This type of bonding means that when the H_2O freezes there is more space between the molecules, then they occupy a larger volume

Therefore, if we have the same mass in the liquid state and the solid-state, the molecules in the liquid state will be closer together occupying less volume (higher density) and the molecules that are in the solid-state occupy a greater volume (lower density)

Almost always true. H2O is the exception as water is more dense than ice.

Jello has a density of 1.14 g/mL. A box of Jello makes 475 mL of Jello and has 13 g of sugar. Determine the % m/m of sugar in the Jello. (Hint: d=m/v) ​

Answers

Answer:

2.34 %

Explanation:

Since the density of the Jello, ρ = 1.14 g/mL and ρ = m/v where m = mass of jello and v = volume of jello = 475 mL.

So, m = ρv

substituting the values of the variables into the equation, we have

m = ρv

m = 1.14 g/mL × 475 mL = 541.5 g

Since we have 13 g of sugar in the jello, the total mass present is 13 g + 541.5 g = 554.5 g

So, the percentage by mass of sugar present % m/m = mass of sugar present/total mass × 100 %

= 13 g/554.5 g × 100 %

= 0.0234 × 100 %

= 2.34 %

So, the percentage by mass of sugar present % m/m = 2.34 %

The statement "matter can be neither created nor destroyed by chemical means, but it can be changed from one form to another" is the chemical law ofa. conservation of energy.
b. conservation of matter.
c. atomic disintegration.
d. definite proportions.

Answers

your answer is b. conservation of matter.

i just took the test

Answer: b. Conservation of matter.

Explanation:

Law of conservation of matter states that matter can neither be created nor destroyed by means of chemical reaction but can be changed from one form to another.

It means that the amount of matter remains the same after a chemical change.

Which of the following is an example of a Brønsted-Lowry base?​

Answers

Final answer:

A Brønsted-Lowry base is a species that accepts a proton (hydrogen ion) from another species. NH3, OH-, and even water itself are examples of Brønsted-Lowry bases, denoting they accept protons.

Explanation:

A Brønsted-Lowry base is a species that can accept a proton (a hydrogen ion) from another species. For instance, in a reaction between water and ammonia, NH3 is the Brønsted-Lowry base because it accepts a proton from water. This means that any species capable of accepting a proton, such as hydroxide ion (OH-), ammonia (NH3), or water itself can be considered a Brønsted-Lowry base.

For example, think about the dissociation of water:
H2O + H2O ⇌ H3O+ + OH-
In this reaction, water is acting as both a Brønsted-Lowry acid and a Brønsted-Lowry base. One water molecule donates a proton and becomes a hydroxide ion (the conjugate base), while the other accepts a proton to become hydronium (the conjugate acid).

Another example would be the ionization of ammonia in water:
NH3 + H2O ⇌ NH4+ + OH-
Here, ammonia (NH3) is the Brønsted-Lowry base as it accepts a proton from water to become ammonium (NH4+).

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