MATHEMATICS MIDDLE SCHOOL

The cost of two tables and three chairs is $705. If the table costs $40 more than the chair,find the cost of the table and the chair

Answers

Answer 1

Answer:

Answer:

the cost of the table is $\$165$

the cost of the chair is $\$125$

Step-by-step explanation:

Let

x-----> the cost of the table

y----> the cost of the chair

we know that

$2x+3y=705$ -----> equation A

$x=y+40$ -----> equation B

substitute equation B in equation A

$2(y+40)+3y=705$

$2y+80+3y=705$

$5y=705-80$

$y=625/5$

$y=\$125$

Find the value of x

$x=y+40$ ----> $x=125+40=\$165$

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Answers

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The missing figure is attached at the end.

Answer:

x4800 inch

Step-by-step explanation:

Can someone help me understand this?

Answers

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Then, divide by 3 on both sides. This gives you y = -6x + 2.

2 is your y intercept and -6 is your slope.

Positive 6x is is subtracted on the left side, which in turn is moved to the right side. As 3y = -6x + 6 another way of saying this would be the inverse of 6x = -6x.

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Answers

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Answers

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Answers

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