How many fluorine atoms bond with calcium to form calcium fluoride?

Answers

Answer 1
Answer:

Answer;

2 fluorine atoms

Explanation;

  • Calcium, a Group 2 metal, commonly forms a calcium ion (Ca2+). On the other hand, fluorine, a Group 7 non-metal, commonly forms a fluoride ion (F-). The necessity of electrical neutrality ensures that 2  Fluoride ions (F-) binds to one Ca2+
  • The charge on calcium is 2+ and the charge on fluoride ions is 1-. It therefore requires 2 fluoride ions to make the compound electrically neutral.
Answer 2
Answer: charge on calcium is 2+ and the charge on fluorideions is 1-. It therefore requires 2 fluoride ions to make the compound ..

Related Questions

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Of these four liquids, which is the most viscous? A. H2O. . B. CCl4. . C. C2H12O6. . D. Hg
Except for oxygen what is another name for a burning reaction?
Hydrogen has three isotopes 1H, 2H, and 3H. What is the difference between these three isotopes?
Which list includes elements with the most similar chemical properties? 1.Br, Ga, Hg 2. Cr, Pb, Xe 3. O, S, Se 4. N, O, F

The student's experiment most likely demonstrates how... A. earthquakes occur along a fault
B. new crusts move at midocean ridges
C. tectonic movements cause hotspot volcanism
D. mountains are created along cracks in Earth plates

Answers

The right answer for the question that is being asked and shown above is that: "D. mountains are created along cracks in Earth plates."The student's experiment most likely demonstrates how D. mountains are created along cracks in Earth plates

Answer:d

Explanation:test

Which of these is NOT a physical property of matter?A)
odor
B)
boiling point
C)
melting point
D)
ability to rust

Answers

It would be the ability to rust because matter takes up space.

Final answer:

The ability to rust is not a physical property of matter, but a chemical one, reflecting a substance's capacity to react with oxygen to form a new substance.

Explanation:

In the list provided, the ability to rust is NOT a physical property of matter. Physical properties include traits that can be observed or measured without changing the composition of the material. Examples include melting point, boiling point, odor, and density. The ability to rust, however, is a chemical property as it indicates a substance's ability to react with oxygen to form a new substance, which involves a change in composition.

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3.50 L of 0.200 M hydrochloric acid is prepared using 12.0 M HCl(aq) stock solution to which water is added. What volume of the stock solution
is required?

a. 7.00 mL
b. 8.40 mL
c. 17.1 mL
d. 58.3 mL

Answers

Answer:

Explanation:

To determine the volume of the stock solution required to prepare 3.50 L of 0.200 M hydro chloric acid, we can use the formula:

M1V1 = M2V2

where:

M1 = concentration of the stock solution

V1 = volume of the stock solution

M2 = desired concentration of the diluted solution

V2 = desired volume of the diluted solution

Let's substitute the given values into the formula:

M1 = 12.0 M

V1 = ?

M2 = 0.200 M

V2 = 3.50 L

Now we can solve for V1:

12.0 M x V1 = 0.200 M x 3.50 L

V1 = (0.200 M x 3.50 L) / 12.0 M

V1 = 0.0583 L

To convert the volume from liters to milliliters, we multiply by 1000:

V1 = 0.0583 L x 1000 mL/L

V1 = 58.3 mL

Therefore, the volume of the stock solution required is 58.3 mL.

So, the correct answer is d. 58.3 mL.

To determine the volume of the stock solution required, we can use the formula:

Molarity1 x Volume1 = Molarity2 x Volume2

Where Molarity1 and Volume1 represent the initial concentration and volume, and Molarity2 and Volume2 represent the final concentration and volume.

Given:

Molarity1 = 12.0 M

Volume1 = ?

Molarity2 = 0.200 M

Volume2 = 3.50 L

Plugging in the values into the formula, we have:

12.0 M x Volume1 = 0.200 M x 3.50 L

Simplifying the equation, we can solve for Volume1:

Volume1 = (0.200 M x 3.50 L) / 12.0 M

Volume1 ≈ 0.0583 L

To convert this to milliliters, we multiply by 1000:

Volume1 ≈ 58.3 mL

Therefore, the volume of the stock solution required is approximately 58.3 mL.

The closest answer option is d. 58.3 mL.

I hope this explanation helps! Let me know if you have any further questions.

Particles in an object are constantly moving. the particles also attract and repel each other. this attraction and movement can be classified as _________.A. Specific heat
B.heat
C.temperature
D. thermal energy

Answers

Answer:

Thermal energy.

Explanation:

Thermal energy is related to heat of the system, so higher the heat in the system more the thermal energy and this will cause more movement. In case of less thermal energy, less movement and hence more attractions.

A) specific heat : it is the heat required to raise the temperature of one unit of a substance by one degree.

B) Heat is not a property of system. It is given and taken out from the system which changes its temperature and thermal energy.

C) Temperature is measurement of heat.

Particles in an object are constantly moving. The particles also attract and repel each other. this attraction and movement can be classified as D.Thermal Energy

Thermal energy is energy that comes from heat, it's part of energy of total energy of any object.

Hope this helps :)

Which of the following ions has a smaller size? Option 1: O2- Option 2: F- Option 3: They have the same size. Option 4: None of the above.

Answers

The fluoride ion (F-) is smaller in size than the oxide ion (O2-).

The ion with a smaller size is F- (fluoride ion) compared to O2- (oxide ion).

The size of an ion depends on the number of protons and electrons it has. Fluoride ion has one less electron than the oxide ion, making it smaller in size.

This trend can be explained by the concept of effective nuclear charge, where the positive charge of the nucleus is partially shielded by other electrons in the atom. As the atomic number increases from oxygen to fluorine, the increase in nuclear charge outweighs the additional electron-electron repulsions, resulting in a smaller size for fluoride ion.

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Please help super emergency!!4.00 x 10^23 molecules of H3PO4 have an approximate mass of
a. 8g.
b. 65g.
c. 147 g.
d. 663g.

Answers

1) we can calculate the molecular weight of H₃PO₄
atomic mass  (H)=1 amu
atomic mass (P)=31 amu
atomic mass (O)=16 amu 

molecular weight (H₃PO₄)=3(1)+31+4(16)=98 amu.

1 mol (H₃PO₄)=98 g
1 mol= 6.022 * 10²³ molecules.

2) we calculate the mass of 4.00*10²³ molecules.

98 g-------------------6.022*10²³ molecules
x------------------------4.00*10²³ molecules

x=(98 g * 4.00*10²³ molecules) / 6.022*10²³ molecules≈65 g

Answer: 65 g