if you have 3.50 moles of hydrogen and 5.00moles of nitrogen to produce ammonia, witch element is the reactant in excess? 3H2+N2=2NH3

Answers

Answer 1
Answer:

Given 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, nitrogen is the excess reactant.

What is the excess reactant?

The excess reactant is the reactant in a chemical reaction with a greater amount than necessary to react completely with the limiting reactant.

  • Step 1: Write the balanced equation.

3 H₂ + N₂ ⇒ 2 NH₃

  • Step 2: Establish the theoretical ratio.

The theoretical ratio (TR) of H₂ to N₂ is 3:1.

  • Step 3: Establish the experimental ratio.

The experimental ratio (ER) of H₂ to N₂ is 3.50:5.00 = 0.70:1.

  • Step 4: Determine the excess reactant.

Comparing TR and ER, we can realize that there is not enough hydrogen to react with the nitrogen. Thus, nitrogen is the excess reactant.

Given 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, nitrogen is the excess reactant.

Learn more about excess reactant here: brainly.com/question/17199947

Answer 2
Answer:

Answer : The N_2 element is the reactant in excess.

Solution :  Given,

Moles of N_2 = 5 moles

Moles of H_2 = 3.50 moles

The balanced chemical reaction is,

3H_2(g)+N_2(g)\rightarrow 2NH_3(g)

From the balanced reaction we conclude that

As, 3 moles of H_2 react with 1 mole of N_2

So, 3.5 moles of H_2 react with (3.5)/(3)=1.16 moles of N_2

The excess of N_2 = 5 - 1.16 = 3.84 moles

That means in the given balanced reaction, H_2 is a limiting reagent because it limits the formation of products and N_2 is an excess reagent.

Hence, the N_2 element is the reactant in excess.


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A substance conducts an electric current when it is in the liquid state. What would the conductivity of the substance in solid form indicate about the type of bond in the substance?A.) If the solid is conductive, the bonds are ionic.
B.) If the solid is not conductive, the bonds are covalent.
C.) If the solid is conductive, the bonds are metallic.
D.) If the solid is not conductive, the bonds are metallic.

Answers

Answer is: C.) If the solid is conductive, the bonds are metallic.

1) Substances with ionic bond conduct an electric current in liquid, but not in solid state, because in liquids ions are mobile, contrary to solids where ions are fixed.

2) Substances with covalent bond not conduct an electric current in liquid and solid state, because they not have free ions or electrons.

3) Substances with metallic  bond conduct an electric current in liquid and solid state, because they have mobile electrons. Most metals have strong metallic bond, because strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.

Answer:C.) If the solid is conductive, the bonds are metallic.

Explanation:

The physical The physical process of evaporation involves -process of evaporation involves...

Answers

The absortion of energy to separate the molecules. In the liquid state the molecules are closer and to manage the separation neededd in the gas state the molecules need energy from the surroundings.

What does it mean that valence electrons in a metal are delocalized?

Answers

Delocalized means that electrons in the metal are not linked only to a single atom or in a bond. Electrons are free to move and around the crystal structure and carry currents. This is why, in metals, there is a term "electron sea".

Answer:

A

Explanation:

When the pressure exerted on a confined gas at constant temperature is doubled, the volume of the gas is

Answers

When the pressure exerted on a confined gas at a constant temperature is doubled, the volume of the gas is halved. I answer to your question is 'halved'. I hope this helps you on your assignment.

Answer: When the pressure exerted on a confined gas at constant temperature is doubled, the volume of the gas is halved.

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.  

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1 = initial pressure of gas = p

V_1 =  initial volume of gas = v

P_2 = final pressure of gas= 2p

V_2 = final volume of gas = ?

Putting values in above equation, we get:

p* v=2p* V_2

V_2=(v)/(2)

Thus the final volume of the gas is half of the initial volume.

Atoms A and X are fictional atoms. Suppose that the standard potential for the reduction of X^2+ is +0.51 V, and the standard potential for the reduction of A^2+ is -0.33. Find the standard potential for an electrochemical cell with the cell reaction that follows.

Answers

While the reaction is not shown, based on those atoms and reduction potentials, the only reasonable favorable equation we can form is:

A(2+) + X -> A + X(2+)

The standard reduction potential for the cell is the cathode's reduction potential minus the anode's reduction potential, or 0.51-(-0.33)=0.84.

If the [H+] in a solution is 1*10^-1 mol/L, what is the [OH]?

Answers

K(w)=[OH⁻][H⁺]  (K(w)=1×10⁻¹⁴)

[OH⁻]=K(w)/[H⁺]
[OH⁻]=(1×10⁻¹⁴)/0.1
[OH⁻]=1×10⁻¹³M

I hope this helps.  Let me know if anything is unclear.