What volume of a 2.00 M stock solution of NaOH is needed to prepare 150. mL of 0.40 M solution?

Answers

Answer 1
Answer:

To find the volume ratios we say m1v1=m2v2

where m1 is the initial molarity, m2 the final molarity, v1 the initial volume, v2 the final volume.in this question m1=2.00M, m2=0.40M v2=150ml

Therefore the expression becomes:  2.00M×v1=0.40M×150mL

                                                           v1=(0.40M×150mL)/2.00M

                                                               =30mL


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Answers

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Answers

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Answers

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Answers

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Answers

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Explanation:

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Answers

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This is the only answer that can be observed without testing gear and with the naked eye.... Hope I helped ^-^