1 7/3 in simplest form

Answers

Answer 1
Answer: It is already in simplest form, since 17 is a prime number.

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Number with 1 decimal place is rounded to the nearest whole numberwhat the smallest number rounds up to 100?
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A total of 234 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student tickets sold was two times the number of adult tickets sold. How many adult tickets were sold?

All parallelograms have 4 sides.

Answers

Answer:

yes

Step-by-step explanation:

a parallelogram is a 4 sided figure

Subtract.
(3x - 8) - (x2 - 5x - 2)

Answers

Answer:

  -x^2 +8x -6

Step-by-step explanation:

Distribute the minus sign and collect terms.

  (3x -8) -(x^2 -5x -2)

  = 3x -8 -x^2 +5x +2

  = -x^2 +8x -6

Sketch a graph of the following inequality and the choose the correct description of the graph: x + y - 5 ≥ 0 Slope is -1, y-intercept is -3, dashed line, shaded below
Slope is -1, y-intercept is -3, dashed line, shaded above
Slope is 1, y-intercept is -3, dashed line, shaded below
Slope is 1, y-intercept is -3, dashed line, shaded above

Answers

Answer:

Slope -1, y intercept +5.

Bold line, shaded above

Step-by-step explanation:

x + y - 5 ≥ 0

y ≥ -x + 5

You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the firstversion, you are given three attempts, and you estimate that your probability of success on any given throw is 0.1.
In the second version, you are given five attempts, but the target is smaller, and you estimate that your probability of
success on any given throw is 0.05. The prizes for the two versions of the game are the same, and you are willing to
assume that the outcomes of your throws are independent. Which version of the game should you choose? (Hint: In
the first version of the game, the probability that you do not get the prize is the probability that you fail on all three
attempts.)

Answers

Answer:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^(3-0)=0.729

And the probability of loss with the first wersion is 0.729

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^(5-0)=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=3, p=0.1)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^(n-x)

Where (nCx) means combinatory and it's given by this formula:

nCx=(n!)/((n-x)! x!)

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^(3-0)=0.729

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

Y \sim Binom(n=5, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(Y)=(nCy)(p)^y (1-p)^(n-y)

Where (nCx) means combinatory and it's given by this formula:

nCy=(n!)/((n-y)! y!)

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^(5-0)=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Chang 0.83 into a fraction

Answers

answer: 83/100

there you go!!!!

Hope it helps

Create a “fraction” with 0.83 in the numerator and 1.0 in the denominator:

0.83/1.0

Move the decimal point in 0.83 two places to the right to turn it into a whole number; move the decimal point in the denominator the same number of places. Do this one decimal place at a time:

0.83/1.0=8.3/10.0=83/100

At this point, you can drop the decimal points and trailing zeros in both the numerator and denominator.

Solve the equation. Show your work.
1/a =6/18

Answers

Hey there, we cross mutliply, 1*18=6*a=18=6a, we flip the equation to 6a=18, divide both sides by 6, 6a/6=18/6. We come up with a answer of a=3