Shera is building a cabinet. She is making wooden braces for the corners of the cabinet. Find the surface area of each brace.
Shera is building a cabinet. She is making wooden braces - 1

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Answer 1
Answer: The correct answer for the question that is being presented above is this one: "28 in^2." 

We have to get the individual area of each surface.
A1 = 1*3*2 = 6
A2 = 1*3*2 = 6
A3 = 1*2*2 = 4
A4 = 2*3*2 = 12
Area = A1 + A2 + A3 + A4 
Area = 6 + 6 + 4 + 12
Area = 28 in^2

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39=1 3/10b solve the equation

Answers


                                            39  =  (1 and 3/10) b

Let's change that ugly mixed number to a fraction
so that we can work with it.

                   (1 and 3/10)  =  (10/10 and 3/10)  =  13/10

Now the equation says     39  = 13/10  b  

We could multiple
each side by 10:              390  =  13 b

Divide each side by 13:    390 / 13  =  30  =  b

Whenever you're trying to solve any equation, the whole idea is: 

-- Do whatever you need to do in order to get the variable all alone
on one side of the equation and everything else on the other side. 

-- You can do anything you want to do on either side of the equation,

BUT ...

-- whatever you do to one side, you must IMMEDIATELY do the same thing
to the other side.

Pythagorean theorem: Show work please




free points!!!!

Answers

so if you have a right triangle with legs legnth a and b and a hypotonuse legnth c, then a^2+b^2=c^2 given in the comments is that a=15 c=20 input and solve 15^2+b^2=20^2 225+b^2=400 subtract 225 from boths ides b^2=175 take square root of both sides b=5√7
The therorem is: 

a^(2) + b^(2) = c^(2)
or, solving for b:
b = \sqrt{c^(2)-a^(2)}

b = \sqrt{20^(2)-15^(2)}
b = √(400-225)
b = √(175)
b \approx 13.23

Mr grant need 30 pieces of felt .he can buy them in packs of 10 or single pieces.what are the different ways mr.grant can buy the felt?

Answers

Mr Grant can buy the felt in a variety of ways. He can buy 3 packs of10 pieces, 30 single pieces, 1 pack of 10 and 20 single pieces, or 2packs of 10 and 10 single pieces. Hope that answered your question foryou!

Solving Systems of Equations by substitution
-5x-8y=17
2x-7y=-17

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\left\{\begin{array}{ccc}-5x-8y=17\n2x-7y=-17\end{array}\right\n\left\{\begin{array}{ccc}-5x=8y+17&/\cdot(-2)\n2x-7y=-17&/\cdot5\end{array}\right\n\n\left\{\begin{array}{ccc}10x=-16y-34\n10x-35y=-85\end{array}\right\n\nsubstitute:\n\n-16y-34-35y=-85\n-51y=-85+34\n-51y=-51\ \ \ \ /:(-51)\ny=1\n\n10x=-16\cdot1-34\n10x=-50\ \ \ \ /:10\nx=-5\n\nSolution:x=-5\ and\ y=1
-5x=17+8y \n x= - (17+8y)/(5) \n 2x-7y=-17 \n 2* (17+8y)/(5) -7y=-17 \n (34+16y)/(5) -7y=-17 \ we \ bring \ to \ the \ same \ denominator \ \n34+16y-35y=-85 \n -19y=-85-34 \n 19y=119 \n y= (119)/(19) \n x= -( 17+ 8* (119)/(19) )/(5) \n x= - ( 17 + (952)/(19) )/(5) \n x= - ( (323+952)/(19))/(5) \n x= -( (1275)/(19) )/(5) \n x= -(1275)/(19) * (1)/(5) \n x= -(255)/(19)

A glacier advances toward the sea 0.004 mile anually. In 2010 the front of the glacier is 6.9 miles from the mouth of the sea. How far will it be from the sea in 2030.By the way if it helps, were learning how to identify hidden problems in multiple-step problems.. So its a multiple step problem, I really don't understand this so some help will really be appreciated.

Answers


You know where the glacier is now, and how far it moves in
one year.  The question is asking how close to the sea it will be
after many years.

Step-1 ... you have to find out how many years

Step-2 ... you have to figure out how far it moves in that many years

Step-3 ... you have to figure out where it is after it moves that far

The first time I worked this problem, I left out  the most important
step ...READ the problem carefully and make SURE you know
the real question.  The first time I worked the problem, I thought
I was done after Step-2. 

============================

Step-1:  How many years is it from 2010 to 2030 ?

               (2030  -  2010)  =  20 years .


Step-2:  How far will the glacier move in 20 years ? 

               It moves 0.004 mile in 1 year.

              In 20 years, it moves 0.004 mile 20 times

              0.004 x 20  = 0.08 mile


Step-3:How far will it be from the sea after all those years ?

              In 2010, when we started watching it, it was 6.9 miles
              from the sea.

              The glacier moves toward the sea.
               In 20 years, it will be  0.08 mile closer to the sea.
               How close will it be ?

               6.9 miles  -  0.08 mile  =  6.82 miles  (if it doesn't melt)

Let x= the length ofan object in meters and y= the length
of the same object in millimeters. Which
is a smaller number, x or y?

Answers

Answer:

y

Step-by-step explanation:

y is smaller because

1 millimeter = 0.001m