1. What is the length of the segment joining the points at (-1,6) and (-5,3) 2. What is the length of the segment joining the points at (-4, 1) and (3,7)

Answers

Answer 1

Answer: QUESTION 1

We want to find the length of the segment joining the points at (-1,6) and (-5,3).

We use the distance formula which is given by the formula,

$d=√((x_2-x_1)^2+(y_2-y_1)^2)$

$d=√(( - 5 - - 1)^2+(3 - 6))^2)$

$d=√(( - 5 + 1)^2+(3 - 6)^2)$

$d=√(( - 4)^2+( - 3)^2)$

$d=√(16+9)$

$d=√(25)$

$d = 5 \: units$

QUESTION 2

We want to find the length of the segment joining at (-4,1) and (3,7).

We use the distance formula to get,

$d = \sqrt{(3 - - 4)^(2) + {(7 - 1)}^(2) }$

$d = \sqrt{(3 + 4)^(2) + {(7 - 1)}^(2) }$

$d = \sqrt{7^(2) + {6}^(2) }$

$d = √(49+ 36 ) .$

$d = √(85 ) \: units$

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The expression 12a+7s is the cost, in dollars, for a adults s students to enter the local marching band competition. Find the total cost for 4 adults and 30 students.Before you delete this I did try on my own and this has been confusing me

Answers

If 12A is equal to one adult, then this means that one adult will cost $12 to enter.
The same applies for the students, if 7s is equal to one student, then the cost of one student is $7.
As you've got four adults, then you need to find the cost of 4, and you do this by multiply 4 by 12.
4x12=$48
As you've got 30 students, you then need to multiply 30 by 7.
30x7=$210.
To find the total cost, you've then got to add $48 and $210 together.
$48+$210= $258.

Therefore, the total cost for 4 adults and 30 students is $258
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a=$4, s=$30

=12($4)+7($30)
=$48+$210
=$258

Factorise 56x + 35. Need to know asap please.

Answers

The answer is 7(8x+5)

What is the value of x when 10(x + 2) = 5(x + 8)

Answers

the answer is x=4. you have to use the distributive property on both sides then begin solving for x.

Use the distributive property to get 10x+20=5x+40. Subtract 5x from both sides to get 5x+20=40. Subtract 20 from both sides to get 5x=20. Divide 5 from both sides to get x=4.

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The endpoints of cd are C (-4,10) and D (-4,10) the coordinates of the midpoint M of CD are

Answers

The endpoints C and D has nomidpoint M.

Step-by-step explanation:

step 1: The given endpoints of C and D are (-4,10) and (-4,10)

step 2: Midpoint formula = ((x1+x2)/2 , (y1+y2)/2)

step 3: Here, C(-4,10) = (x1,y1)

D(-4,10) = (x2,y2)

step 4: The midpoint represents the half distance of the line CD. Since C and D are same points, they cannot form a line. Therefore, the endpoints CD have no midpoint.

Describe and correct the error in telling whether the two figures are congruent?

Answers

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When figures are CONGRUENT, they have the SAME SIZE, SIDE LENGTHS OR WIDTH, And ANGLES

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