Enter the value of n so that the expression (ny + 25.7) + (–45.2y + 13.9) is equivalent to (–33.7y + 39.6).

Answers

Answer 1
Answer:

Answer:

n=11.5

Step-by-step explanation:

we have

(ny+25.7)+(-45.2y+13.9)=(-33.7y+39.6)

Group terms than contain the same variable in the left side of the equation

(ny-45.2y)+(25.7+13.9)=(-33.7y+39.6)

Combine like terms in the left side

(ny-45.2y)+(39.6)=(-33.7y+39.6)

Simplify

ny-45.2y=-33.7y

ny=-33.7y+45.2

ny=11.5y

Simplify the y

n=11.5


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Michael plans to buy a new car for $25,000. If he saves $1220 a month for it, in how many months will Michael be able to buy the car? Write an inequality and solve.

Answers

The inequality would be $1,200m>$25,000 and solves it would be m>20.4918 months

The cost, £C, of hiring a lorry to travel n miles is given by C=a+bn
where a and b are constants.
The cost of travelling 100 miles is £82. the cost of travelling 250 miles is £157

a find out the value of a and b
b work out the cost of hiring a lorry to travel 300 miles

Please show working out clearly, ill award a brainliest answer!!!!!

Answers

Answer:

Part a) a = 32 and b = 0.5

Part b) £182 is the cost of hiring.

Step-by-step explanation:

Given expression is C = a + bn

where C is the cost of hiring a lorry, n is the distance covered and a, b are two constants.

Part a).

We have to find the constants a and b.

Now we will find the system of equations to find the value of constants.

The cost of travelling 100 miles is £82.

82 = a + 100b ---------(1)

The cost of travelling 250 miles is £157

157 = a + 250b --------(2)

Now we will subtract equation 2 from 1.

157 - 82 = (a + 250b) - (a + 100b)

75 = 150b

b =  (75)/(150)=0.5

Now we put the value of b in equation 1

82 = a + 100×(0.5)

82 = a + 50

a = 82 - 50 = 32

a = 32 and b = 0.5

Part b).

We have to find the cost of hiring a lorry to travel 300 miles.

C = a + bn

C = 32 + (0.5)(300)

C = 32 + 150

C = £182

Part A:
C= a + bn

Make the two equations out of the words:
82 = a + b100 * 2.5     = 205 = a + b250
157 = a+ b250

Subtract the two,
205 = a + b250
- ( 157 = a + b250)
48 = a

Find b by substituting in a:
82 = a + b100
82 = 48 + b100
34 = b100
b = 0.34
Answer for part a: a = 48 , b = 0.34

Part B:
C = a +bn    <- when n = 300   , put in a and b, then solve
C = 48 + 0.34(300)
C = 48 + 102
C = 150

Cost when hiring a lorry to travel 300 miles is 150 pounds

Find the constant of proportionality and unit rate for the data in the table. Then write the equation to represent the relationship between time t and distance d Time Distance
2 hrs 90 miles
3 hrs 135 miles
5 hrs 225 miles
6 hrs 270 miles

I dont understand how to do this kind of math.Please help

Answers


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Answers

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Answers

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Answers

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