What is the mass of 2.25 moles of manganese(lv) sulfide(MnS2)

Answers

Answer 1
Answer:

Explanation:

Number of moles is defined as mass divided by molar mass of the substance or atom.

Mathematically,     No. of moles = (mass)/(molar mass)

It is known that molar mass of MnS_(2) is 119.058 g/mol and number of moles is given as 2.25 mol.

Therefore, calculate mass of MnS_(2) as follows.

                          No. of moles = (mass)/(molar mass)

                                   2.25 mol = (mass)/(119.058 g/mol)

                                 mass = 267.88 g

Thus, we can conclude that mass of 2.25 moles of manganese(lv) sulfide(MnS2) is 267.88 g.

                 

Answer 2
Answer:

Final answer:

The mass of 2.25 moles of Manganese (V) Sulfide (MnS2) can be calculated by multiplying the molar mass of MnS2 (119.08 g/mol) by the number of moles (2.25). The result is approximately 267.93 grams.

Explanation:

The question asks about the mass of 2.25 moles of manganese (V) Sulfide (MnS2). We can calculate this using the molar mass of MnS2. The molar mass of manganese (Mn) is approximately 54.94 g/mol, and the molar mass of Sulfur (S) is approximately 32.07 g/mol. To find the molar mass of MnS2 we add up the molar mass of Mn and twice the molar mass of S (because we have 2 S atoms). Therefore the molar mass of MnS2 = 54.94 + 2*(32.07) = 119.08 g/mol. To find the mass in grams, we multiply this molar mass by the number of moles. Hence, the mass of 2.25 moles of MnS2 = 2.25 * 119.08 = 267.93 grams.

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c. deliquescent
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Answers

Let us understand all the terms

Hydration : this is the addition of water to anything. It can be addition of water to double or triple bond, absorption of water by a substance. so it cannot be loss of water.

Deliquescent : it is the absorption of water by a substance and getting dissolved in it. Like NaOH is a deliquescent substance.

Solvation: It is the phenomenon where a substance get surrounded by solvent molecules. If solvent is water it is known as hydration.

Thus the answer is

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How many grams of CuSO4 are there in 100.0 g of hydrate? How many moles?

Answers

the hydrate form of CuSO4 has 5 water molecules (CuSO4-5H20) copper (II) Sulfate pentahydrate or commonly known as blue vitriol. 

To solve, the following molar masses are to be known. 
CuSO4.5H2O (hydrate)  - 249.7g/mole
CuSO4 (anhydrous) -159.6g/mole
Also there molar ratio of the hydrate and CuSO4 is 1. 

the mass of the hydrate is to be divided by the molar mass of the hydrate then multiplied by the ratio (1) to get the moles of hydrate and multiplied by the molar mass of the anhydrous to get the mass in grams. 

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A sample of calcium oxide (CaO) has a mass of 2.80 g. The molar mass of CaO is 56.08 g/mol. How many moles of CaO does this sample contain?

Answers

Answer is "0.05 mol".

Explanation;

We can do calculation by using a simple formula as

n = m/M

Where, n is the number of moles of the substance (mol), m is the mass of the substance (g) and M is the molar mass of the substance (g/mol).

Here,

n = ?

m = 2.80 g

M = 56.08 g/mol

By substitution,

n = 2.80 g /56.08 g/mol

n = 0.0499 mol ≈ 0.05 mol

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Answers

Answer:

Option A is correct.

A.The potential energy in the system is greatest at X.

Explanation:

A ball resting at the top of a hill will have greatest potential energy because when an object is at rest it tend to have greatest potential energy. When It moves from position X to Y the potential energy of the ball will decrease and its kinetic energy will increase.

Answer choices are listed below.

A.The potential energy in the system is greatest at X.

B.The kinetic energy in the system is greatest at X. 
C.Total energy in the system decreases as the ball moves from X to Y.
D.Total energy in the system increases as the ball moves from X to Y.

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Answers

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Answers

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