MATHEMATICS MIDDLE SCHOOL

PLEASE RESPOND IN DESCRIPTION. "Mrs. Wheeler goes to the bakery with $30. She purchases 2 loaves of bread for $3.50 each and a dozen donuts for$9. She plans to spend the remainder of her money on cookies that cost $1.50 each. What is the greatest number of cookies that Mrs. Wheeler can buy?"

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:3.50

*2=7 + 9 = 16

30-16=14 1.50 * 9 =13.50$

Answer 2

Answer:

Answer:

Step-by-step explanation:

Bread = $7

12 donuts = $9

That equals $16.

Cookies cost $1.50,

$1.50 x 9 = $13.50.

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8% of what number is 16

Answers

200, because 8% is 8 parts of 100%. Then 1 part of that 100% is 16/8=2. Then 100% is the number i.e; 200

8% of 100, is 16/8 is, 2 times 100 is 200

Answer: 200

0.000033 in scientific notation?!

Answers

we know that

$0.000033=(33)/(1,000,000) =(33)/(1*10^(6)) =33*10^(-6) =3.3*10^(-5)$

therefore

the answer is $3.3*10^(-5)$

3.3 times -10 to the fifth power.

The surface area of a right triangular prism is 228 square inches. The base is a right triangle with a base height of 6 inches and a base length of 8 inches. The length of the third side of the bae is 10 inches. Find the height of the prism.Please help meeeee!!!!!!

Answers

Answer:

The height of right triangular prism is 7.5 in.

Step-by-step explanation:

The base is a right triangle with a base height of 6 inches and a base length of 8 inches. The length of the third side of the base is 10 inches.

The area of a triangle is

$A=(1)/(2)\tims base* height$

$A_1=(1)/(2)\tims 6* 8=24$

Let the height of the prism be h.

Area of a rectangle is

$A=length* width$

$A_2=6* h=6h$

$A_3=8* h=8h$

$A_4=10* h=10h$

The surface area of a right triangular prism is

$A=2* \text{Area of base}+\text{Area of three rectangles}$

$A=2* (A_1)+A_2+A_3+A_4$

$A=2* (24)+6h+8h+10h$

$A=48+24h$

The surface area of a right triangular prism is 228 square inches.

$228=48+24h$

$180=24h$

$h=7.5$

Therefore the height of right triangular prism is 7.5 in.

$look\ at\ the\ picture\n\nArea=228\ in^2\n\nArea=2A_1+A_2+A_3+A_4\n\n2A_1=2\cdot(6\cdot8)/(2)=48\ (in^2)\n\nA_2=8H\n\nA_3=6H\n\nA_4=10H$

$48+8H+6H+10H=228\n\n48+24H=228\ \ \ /-48\n\n24H=180\ \ \ /:24\n\nH=7.5\ (in)$

Help me on this problem please