Write the sentence as an equation. 323 decreased by d equals 369

Answers

Answer 1
Answer: 323 - d = 369

Thus, d has to be negative, and you get:

-d = 46
d = -46


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What is x+5 over x = 5 over 4

Answers

x\not=0\n\n(x+5)/(x)=(5)/(4)\n5x=4(x+5)\n5x=4x+20\n5x-4x=20\nx=20

Determine whether each expression is equivalent to −9.8+(−4.3).Select Yes or No for each expression.
−9.8−4.3
Yes
No
−9.8+(−0.2)+(−4.1)
Yes
No
−9.8−0.2+4.1
Yes
No
−9.8+(−0.2−4.5)
Yes
No
−9.8+0.2−4.5
Yes
No

Answers

a=yes
b=yes
c=no
d=no
e=yes

Answer:

^^^^

Step-by-step explanation:

The formula for the area of a square is s2, where s is the side length of the square. What is therea of a square with a side length of 6 centimeters? Do not include units in your answer

Answers

Answer:

36

Step-by-step explanation:

Area of a square is , where 's' is the side length.

For a square of side length = 6 cm ,

The area = (6 cm)² = 36 cm²

* Why did your teacher say that you should not include units in your answer?

Anyway, the area without units is 36 .

Hot Air Balloon 1 is 10 meters above the ground, rising 15 meters per minute, and Hot Air Balloon 2 is 150 meters above the ground descending 20 meters per minute. In how many minutes will the balloons be at the same height?
How high will the balloons be at that time?
(Let x represent the time and y represent the height)

Answers

The time at which the ballons are at the same height is 4 minutes and the height of the ballons at that time is 70 meters and this can be determined by using the given data.

Given :

  • Hot Air Balloon 1 is 10 meters above the ground, rising 15 meters per minute.
  • Hot Air Balloon 2 is 150 meters above the ground descending 20 meters per minute.

The following steps can be used in order to determine the time in minutes at which the balloons be at the same height and also the height of the ballons:

Step 1 - The height of balloon 1 from the ground is:

H_1= 10+15t

where 't' is the time.

Step 2 - The height of balloon 2 from the ground is:

H_2= 150-20t

where 't' is the time.

Step 3 - So, the time at which the ballons are at the same height is calculated as:

\begin{aligned}\n15t +10&=150-20t\n35t &= 140\nt& = 4\;{\rm minutes}\n\end{aligned}

Step 4 - So, the height of the ballons at (t = 4) is:

{\rm Height} = 10+15* (4)

{\rm Height} = 70\;{\rm meters}

The time at which the ballons are at the same height is 4 minutes and the height of the ballons at that time is 70 meters.

For more information, refer to the link given below:

brainly.com/question/10726356

You have two equations
y = 10 + 15x   and    y = 150 - 20x
since  y = y   you can get
10 + 15x = 150 - 20x    now we solve for x
      +20x         +20x     add 20x to both sides
10 + 35x = 150    now subtract 10 from both sides
-10             -10
35x = 140    then divide both sides by 35
/35      /35
so  x = 4 minutes

to find what high they are at 4 minutes
plug 4 back into the equation for x
y = 10 + 15(4) = 10 + 60 = 70
so  70 meters from the ground

The lenght of a rectangular classroom floor is 19 feel less than twice the width which expression repersents the area of the classroom floor

Answers

w*(2w-19)=A. Just make the width a variable and write out the relationship it has with the length

distribution of expenses for sales of 240,000 ace manufacturing company how many dollars were spent for operating expenses

Answers

labor cost = 240000 *0.4 = 96000