Divide £50.00 in a ratio of 1:4 SOMEBODY HELP ME NOW!

Answers

Answer 1

Answer: 12.5 would be the answer

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Round the number to the thousandths place.64,672.318498
a. 64,672.318
b. 65,000
c. 64,672.32
d. 64,672.319

Answers

Thousandths is to three decimal places to the right.

Because 4 (the fourth digit) is less than 5, the 8 is left as it is.
Therefore, the answer is 64672.318

The answer is a.

Yh plss I need an answer to this question plss

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Question:

A boy makes a cone of diameter 28 cm without a base. He then cuts a smaller cone of diameter 20 cm from the cone. He used the bottom part as a lampshade. If the height of the lampshade is 11cm,

(a) find the volume of the whole cone.

(b) find in cm2, the area of the material used to make the lampshade.

Answer:

(a) V ≈ 16420.1

(b) A ≈ 2690.1 cm²

Step-by-step explanation:

Solution for (a)

Formula: The formula for the volume of a cone is V = 1/3 hπr².

V= πr² h/3 = π × 28/ 2 × 20/ 3 ≈ 16420.0576

16420.0576 in nearest tenths is 16420.1

Therefore, the volume of the whole cone is 16420.1 cm²

Solution for (b)

Formula: A = πrl + πr2.

l = r² + h²

Solving for A

A = πr (r + h²+ r²) = π × 20 × (20 + 112 + 202) ≈ 2690.80077

2690.80077 In nearest tenths, is 2690.1

Therefore, the area of the material used to make the lampshade is 2690.1 cm²

The area of a rhombus equals half the sum of the diagonals

Answers

The statement is TRUE. There are a lot of formula in getting the area of the rhombus because it is a special shape or a special perpendicular. Dividing the sum of the 2 diagonals divided by 2 is just one way to solve the area. It can also be solve by multiplying the base and the height.

Help with radicals, questions down in attachments.

Answers

we can't solve first 2 because of missing diagramd
but, longest side=hypotonuse=c
other 2 sides=legs=a and b
a^2+b^2=c^2
$\sqrt{a^(2)+b^(2)}=c$

last 2
1.
remember that
longest side<sum of other 2 sides or else you can't make a traignel
5+7=12
12<13
13 is longest side
13<12 is false
therefor it is false that it is a triangle
not a triangle

2.
$\sqrt{ (x)/(y) } = ( √(x) )/( √(y) )$ so
$\sqrt{ (20)/(7) } = ( √(20) )/( √(7) )$ = $(4√(5) )/(√(7) )$
rationalize denomeator by multplying by $( √(7) )/( √(7) )$

$(4√(35) )/(7)$

I rent a gym for $150.00 for 30 students. Another time I rent the gym for $270.00 for 70 students. I need to find a fixed rate.(y= mx+b)

Answers

Answer: y = 3x + 60

Step-by-step explanation:

Set up two equations and solve the system:

270 = 70x + b

- (150 = 30x + b)

120 = 40x

3 = x

Input "x" into one of the equations and solve for "b":

150 = 30x + b

150 = 30(3) + b

150 = 90 + b

60 = b

Equation: y = 3x + 60

This means that there is a flat fee of $60 plus a rate of $3 per student

The fixed rate of gym fee of $60 plus a rate of $3 per student.

The fixed-rate is;

$\rm y=3x+60$

Given

I rent a gym for $150.00 for 30 students.

Another time I rent the gym for $270.00 for 70 students.

Linear function;

A linear function is a function that forms a straight line in a graph.

Let x be the number of students and y be the total cost of renting the gym.

To find the fixed-rate let us write the equation of line representing the total cost of renting a gym for x students.

The equation representing a fixed rate is;

$\rm y = mx+b$

I rent a gym for $150.00 for 30 students.

$\rm 150 = 30x + b$

Another time I rent the gym for $270.00 for 70 students.

$\rm 270 = 70x + b$

Subtracting both the equations;

$\rm 150-270=30x+b-70x-b\n\n-120=-40x\n\n120=4x\n\nx=(120)/(4)\n\nx=3$

Substitute the value of x in equation 1

$\rm 150 = 30x + b\n\n150=30(3)+b\n\n150=90+b\n\nb=150-90\n\nb=60$

Therefore,

The fixed-rate is;

$\rm y=mx+b\n\ny=3x+60$

Hence, the fixed rate of gym fee of $60 plus a rate of $3 per student.'

To know more about linearfunction click the link given below.

brainly.com/question/371915

Rewrite the equation 2x + 4y + 2 = 3y + 5 in general form.

Answers

Answer: The required general form of the given equation is

$2x+y=3.$

Step-by-step explanation: We are given to rewrite the following equation in general form :

$2x+4y+2=3y+5~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We know that

the general form of a linear equation in two variables x and y is written as :

$ax+by=c,~~\textup{[where a and b cannot be zero at the same time]}$

So, from equation (i0, we have

$2x+4y+2=3y+5\n\n\Rightarrow 2x+4y-3y=5-2\n\n\Rightarrow 2x+y=3.$

Thus, the required general form of the given equation is

$2x+y=3.$

I believe that the general form would be 2x +4y+ 2 = 3y + 5
2x + 4y + 2 - 3y - 5 = 0
2x + y - 3 = 0

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