The Appalachian trail is roughly 2,180 miles long. About how long is the trail in kilometer?

Answers

Answer 1
Answer:   1 mile = 1.609344... kilometer

           2,180 miles = (1.609344... x 2,180 km)

                               =          3,508.37 km      (rounded) 

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an electronics store had 182 video games. if they put them on shelves with 24 on each shelf, about how many shelves would they need?

Answers

182 games24 on each shelfbasicaalyx shelves is more than or equal to 182 games1 shelf=24x times 24>182divide both sides by 24x>7 and 4/24x has to be a whole number since you can't have fractional shelvesyou have to have more shelves since less shelves won't allow you to carry all of themround up7 and something rounded u is 8

 8 shelves (if you are a weird store that has fractional shelves then the answer is 7 and 1/6 shelves)
To figure that out, I am going to divide 182÷24 to get my answer so 182÷24=7.583 and I want a whole number so I am going to round it up to 8 so I think they need 8 shelves.



In an A.P,the sum of first ten terms is -150 and the sum of next 10 terms is -550.Find the A.P

Answers

S10 = -150;
 the sum of next 10 terms = S20 - S10 => -550 = S20  + 150 => S20 = -700;
S10 = -150 => 2a1 + 9r = -30;
 S20 = -700 => 2a1 + 19r = -70;
Then 10r = -40 => r = -4 , and, 2a1 -36 = -30 => 2a1 = 6 => a1 = 3;

a rectangular garden has dimensions of 100 feet by 10, next season, the garden decreased to 2/5 of its size. what is the scale of the drawing for the new garden

Answers

Answer: 40 ft by 4 ft

Step-by-step explanation:

See attached picture

One side of a triangular garden is x feet long. The other two sides of the garden are both 5 feet less than twice the length of the first side of the garden.Part A: Write a simpiflied expression for perimeter, in feet, of the garden.
A fence is placed along the entire perimeter of the triangular garden. The roll of fencing is 40 ft long.
Part B: Write a simplified expression to show the amount of fencing, in feet, which is left from the roll of fencing.

Answers

A:  If the 1st side of the garden is x feet long then the other sides are 2x - 5.  The perimeter is simply the measure of the distance around the triangle, so the length of all three sides added up.  So the equation to find the perimeter (p) would be...

p = x + (2x+5) + (2x+5)
or
p = x + 2(2x+5)

This is actually an equation so the expression to represent perimeter would simply be...

x + 2(2x+5)

B:  Since we know the equation for the perimeter and we know that we have 40 feet of fencing, then the equation to find the left over fencing would just be the length of fencing minus the perimeter...

40 - x + 2(2x+5) = the leftover amount of fencing

so the expression is...

40 - x + 2(2x+5)


Help me please
!!!!!!!!!!!!!!!

Answers

S is in negative territory. So it is going to take you a distance to get to 0 and move further right to T.

You can do this without a formula just by adding 2 to get to zero and then 14 more to get to T. The distance between S and T is 14 + 2 = 16.

Now we should develop some kind of formula for these questions. When one point is on one side of zero on the number line and the other point is on the other side of zero then the formula for distance is

distance (as a formula for this question) = abs(S) + abs(T)

Distance = abs(-2) + abs(14) = 2 + 14 = 16

When both point are on the same side of zero then the formula becomes

Distance= abs(abs(S) - abs(T) )

For example if S = -2 and T = - 9

Then the distance = abs( abs(-2) - abs(-9) ) = abs(2 - 9) = abs(-7) = 7

If you have not taken abs value, then just take the answer that I have given above.

The distance between S and T:

|-2| + 14

= 2 + 14

= 16

Answer

16 units

Solving equations. find value of m2m - 1/2 = m/7 + m/2

here is a picture of the previous question

Answers

2m-\frac { 1 }{ 2 } =\frac { m }{ 7 } +\frac { m }{ 2 } \n \n \frac { 1 }{ m } \left( 2m-\frac { 1 }{ 2 }  \right) =\frac { 1 }{ m } \left( \frac { m }{ 7 } +\frac { m }{ 2 }  \right)

\n \n \frac { 2m }{ m } -\frac { 1 }{ 2m } =\frac { m }{ 7m } +\frac { m }{ 2m } \n \n 2-\frac { 1 }{ 2m } =\frac { 1 }{ 7 } +\frac { 1 }{ 2 } \n \n 2-\frac { 1 }{ 7 } -\frac { 1 }{ 2 } =\frac { 1 }{ 2m }

\n \n \frac { 28 }{ 14 } -\frac { 2 }{ 14 } -\frac { 7 }{ 14 } =\frac { 1 }{ 2m } \n \n \frac { 19 }{ 14 } =\frac { 1 }{ 2m } \n \n { \left( 2m \right)  }^( -1 )={ \left( \frac { 14 }{ 19 }  \right)  }^( -1 )

\n \n 2m=\frac { 14 }{ 19 } \n \n \frac { 1 }{ 2 } \cdot 2m=\frac { 14 }{ 19 } \cdot \frac { 1 }{ 2 } \n \n m=\frac { 14 }{ 38 } =\frac { 7 }{ 19 }