there is no choices but A binary compound is a compound composed of only two elements. Binary compounds composed of a metal and a non metal and are named as ionic compounds.
Lithium fluoride LiF
Lithium chloride LiCl
Lithium phosphide Li3P
Beryllium fluoride BeF2
Beryllium chloride BeCl2
Beryllium bromide BeBr2
Beryllium iodide BeI2
Beryllium phosphide Be3P2
Boron fluoride BF3
Boron chloride BCl3
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A binary ionic compound is composed of ions of two different elements - one of which is a metal, and the other a nonmetal.
The chemical reaction produces a new substance with new and different physical and chemical properties. Matter is never destroyed or created in chemical reactions. The particles of one substance are rearranged to form a new substance. .
Answer:
Noho3 helps rise the cookies
Explanation:
It airs out the dough
Answer: C3H4 (Propayne) have a triple bond.
Explanation:
The hydrocarbons which having triple bond are called alkyne. The general formula of alkyne is CnH2n-2. Here, n is number of carbon atoms.
In alkyne, the number of hydrogen atom is 2 less than double the number of carbon atoms.
Thus, the compound C3H4 (Propyne) have a triple bond.
A. 17
B. 12
C. 15
D. 11
apexs anwers is B.12
Answer:
Answer:
12
Explanation:
find the median:
19
find median of 10, 11, 12, 15, 17
median: 12
Answer:
There will be produced 66g of CO2 if 45g of glucose completely reacted with oxygen
Explanation:
Step 1 : Balance the formula
Oxidation of glucose can be shown in the following equation :
C6H12O6 + 6 O2 → 6 CO2 + 6H2O
This means that for 1 mole glucose that react there will react 6 moles of O2, to form 6 moles of CO2 and 6 moles of H2O
Step 2: Calculating moles
mole glucose = 45g / Molar mass glucose
⇒ Molar mass = 6*12 + 12*1 + 6*16 = 72 + 12 + 96 = 180g/mole
⇒ mole glucose = 45g / 180g/mole
⇒mole glucose = 0.25 mole
Since 1 mole of glucose is used to form 6 moles of CO2
0.25 mole of glucose is used to form 1.5 moles of CO2
Step 3 : Calculating mass of Carbon dioxide
Mass of CO2 = 1.5 moles of CO2 * 44 g/mole
mass of CO2 = 66g
There will be produced 66g of CO2 if 45g of glucose completely reacted with oxygen
If 45g of glucose reacts with oxygen, 66.015 grams of carbon dioxide would be produced. This calculation is based on converting the mass of glucose to moles, using the stoichiometry of the balanced chemical equation, and then calculating the mass of CO2 produced.
When glucose (which has the chemical formula C6H12O6) is consumed, it reacts with oxygen to produce carbon dioxide, water, and energy. The chemical equation for this reaction is C6H12O6 + 6 O2 → 6 CO2 + 6 H2O. Given that 45g of C6H12O6 completely reacts with oxygen, we need to calculate the mass of carbon dioxide produced from this reaction.
To do this, we first need to determine the molar mass of glucose, which is 180.16 g/mol. This means that 1 mole of glucose weighs 180.16 grams. We can then find out how many moles of glucose 45g represents by dividing 45g by 180.16 g/mol, which gives us 0.25 mol of glucose.
According to the chemical equation, 1 mole of glucose produces 6 moles of CO2. Therefore, 0.25 moles of glucose would produce 0.25 × 6 = 1.5 moles of CO2. The molar mass of CO2 is 44.01 g/mol, so the mass of CO2 produced by 0.25 moles of glucose is 1.5 moles × 44.01 g/mol, resulting in 66.015 grams of CO2. So, if 45g of C6H12O6 completely reacted with oxygen, 66.015 grams of CO2 would be produced.