Jarred wants to buy a go-cart for $1,200. His part-time job pays him $160 a week. He has already saved $400. Which inequality represents the minimum number of weeks (w) he needs to work, in order to have enough money to buy the go-cart?
Answers
Hello!
The answer is:
Why?
First, we need to find the money that Jarred needs including the money that he has already saved.
So, Jarred needs $800.
If he earns $160 a week, we can find the minimum weeks he has to work in order to earn $800 following the next steps:
So, if he has to work at least 5 weeks to earn the total amount of money, it can be expressed by the following inequality:
Have a nice day!
Final answer:
Jarred has to save $800 more to buy the go-cart, that is $1,200 minus the $400 he already saved. If he earns $160 per week, the inequality representing the minimal number of weeks he has to work is: 160w >= 800. If we solve this inequality for w, we find that w must be equal or greater than 5 weeks.
Explanation:
This question is about solving inequalities. The cost of the go-cart is $1,200 and Jarred has already saved $400. That leaves him with $800 he still needs to save.
His job pays him $160 a week. Therefore, we can identify the inequality as 160w + 400 ≥ 1,200.
To determine the minimum number of weeks Jarred needs to work, we solve for w
Steps to solve:
- Subtract 400 from both sides of the equation to isolate the term with w: 160w ≥ 800.
- Divide both sides by 160 to solve for w: w ≥ 5.
- As you cannot work a fraction of a week, the minimum number of weeks he needs to work is 5.
Learn more about inequalities here:
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Hope I helped anyways! :)
Answers
Answer:
The correct option is 4.
Step-by-step explanation:
It is given that 120% of a number is 43.
Let the number be x.
Multiply both sides by 10.
Divide both sides by 12.
The required number is 35.83. Therefore the correct option is 4.
Answers
Answer:
The maximum height (vertex) is at (0,256), which is also when it began (Y-Intercept). It will take 4 units for it to hit the ground.
Let us know how you do on the test.
Answers
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
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hence proved
{(-5, 6), (-3, 13), (-14, 30)}
{(12, 12), (12, 13), (12, 14)}
Answers
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{(12, 12), (12, 13), (12, 14)} and {(1, 3), (4, 5), (4, 9), (6, 19)} are not a function
Answer:
the second set
Step-by-step explanation:
You cannot have the same number in your domain twice.