Is it possible that image of a point after a reflection could be the same as the preimage?

Answers

Answer 1
Answer: Sure. The point is ON the line of reflection.

Related Questions

Solve 3(x-4)= -5 for x.
Line RS is tangent to circle Q at point R.What is the measure of ∠SQR ? Enter your answer in the box.
The product of half my number times my number is 162.what is my twice my number
How do you solve this 3 = 4x+31/5
Which figure could be rotated the least amount of degrees to be carried onto itself

What are the solutions of x^2 - 5x+7 = 0 ?​

Answers

Answer:

C.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=(-b\pm√(b^2-4ac) )/(2a)

Algebra II

  • Imaginary Roots: √-1 = i

Step-by-step explanation:

Step 1: Define

x² - 5x + 7 = 0

Step 2: Identify Variables

a = 1

b = -5

c = 7

Step 3: Find solutions

  1. Substitute [Quad Formula]:                    x=(5\pm√((-5)^2-4(1)(7)) )/(2(1))
  2. Evaluate Exponents:                               x=(5\pm√(25-4(1)(7)) )/(2(1))
  3. Evaluate Multiplication:                          x=(5\pm√(25-28) )/(2)
  4. Evaluate Subtraction:                             x=(5\pm√(-3) )/(2)
  5. Factor:                                                     x=(5\pm√(-1) √(3) )/(2)
  6. Simplify:                                                  x=(5\pm i√(3) )/(2)

The solutions to the equation x² - 5x + 7 = 0  are:

x = (5 + i√3) / 2 or x = (5 - i√3) / 2

Option C is the correct answer.

We have,

To find the solutions of the quadraticequation x² - 5x + 7 = 0, we can use the quadraticformula:

x = (-b ± √(b² - 4ac)) / (2a)

For the given equation, the coefficients are:

a = 1

b = -5

c = 7

Substituting these values into the quadraticformula,

x = (-(-5) ± √((-5)² - 4(1)(7))) / (2(1))

Simplifying further:

x = (5 ± √(25 - 28)) / 2

x = (5 ± √(-3)) / 2

Since the discriminant (the value inside the square root) is negative, √(-3) is imaginary, meaning there are norealsolutions to this quadratic equation.

The solutions exist in the complex number system.

So,

√-1 = i

x = (5 ± i√3) / 2

This can be written as,

x = (5 + i√3) / 2

and

x = (5 - i√3) / 2

Thus,

The solutions to the equation x² - 5x + 7 = 0  are:

x = (5 + i√3) / 2 or x = (5 - i√3) / 2

Learn more about solutionsofequations here:

brainly.com/question/545403

#SPJ6

Can someone help me find the volume of this cone?

Answers

7. V= 1/2bh
V=1/2*14*25
V=175yd^2

5. V=1/2bh
V=1/2*24*25
V=300m^2

3x + y = 17
4x - y = 18

Answers

The two equations given are
3x + y = 17 and 4x - y = 18
Now we will first take one equation
3x + y = 17
Then
y = 17 - 3x
Now replacing the value of y in the second equation we get
4x - y = 18
4x - (17 - 3x) = 18
4x + 3x - 17 = 18
7x = 35
 x = 35/7
   = 5
Putting the value of x in the first equation we get
3x + y = 17
(3 * 5) + y = 17
15 + y = 17
y = 17 - 15
y = 2
So the value of x is 5 and y is 2
3x+y=17
subtract 3x on both sides
y=17-3x
substitute 17-3x for y in the second equation
4x-(17-3x)=18
7x-17=18
7x=35
x=5

and now that you know x=5 you can plug that in to either of the original equations
3(5)+y=17
15+y=17
subtract 15 from both sides
y=2

Consider the figure above. Starting with the shape in the upper left, identify the figure that has been: -Translated only. -Rotated and translated. -Reflected about the x-axis.

Answers

The figure which is rotated and translated correctly about the x-axis is figure a.

What is graph?

The graph of a function f is that the set of ordered pairs, where\f(x)=y. within the common case where x and f(x) are real numbers, these pairs are Cartesian coordinates of points in two-dimensional space and thus form a subset of this plane.

How to form graph of function?

We have been given four graphs of a function and first function has coordinates (-5,7) (-2,6) (-7,4) (-4,1) and that we must identify correct reflected graph.

The coordinates of a pure reflected graph are going to be (4,7) (2,4) (5,1) (7,6) which are the coordinates of figure a which is in first quadrant.

Hence the proper reflected graph of function having coordinates (-5,7) (-2,6) (-7,4) (-4,1) is that the graph of coordinates (4,7) (2,4) (5,1) (7,6).

Learn more about function at brainly.com/question/10439235

#SPJ2

Answers:

Figure a has been translated only (translated 9 units to the right)

Figure b has been reflected over the x axis

Figure c has been rotated and translated

=======================================

Explanation:

Pick on a point like (-7,4) and note how it moves 9 units to the right to get to (2,4). All points on the upper left figure follow this same translation rule. This rules in figure a.

Figure b is a result of reflecting over the x axis. The rule used is (x,y) \to (x,-y). The x coordinate stays the same while the y coordinate flips from positive to negative. So for example, (-7,4) flips to (-7,-4)

Figure c is a combination of rotating and translating the original figure. It looks like a 90 counterclockwise rotation has been applied followed by a translation. The actual translation and rotation rules used will depend on how you define the center of rotation.

Square root of 200 in radical form

Answers

10 √2 is the radical form of √200
The square root of 200 in radical form is 10√2

What is the sum of (1.3 × 10-7) and (-3.8 × 10-3)?A. 2.5 × 10-10
B. -2.5 × 10-4
C. 3.8 × 10-3
D. -3.8 × 10-3

Answers

1.3 x 10⁻⁷ + -3.9 x 10⁻³

1.3 x 10⁻⁷ = 0.00000013
-3.9 x 10⁻³ = -0.0039

-  0.00390000
0.00000013   
 - 0.00389987  -3.8 x 10⁻³  CHOICE D.