In a 30-minutes television show, The number of minutes of programming is six more than twice the number of minutes of advertisements. How many minutes of programming is there

Answers

Answer 1

Answer: You have x number of minutes of advertisements. Programming is 6 minutes more than 2 times the ads so it can be expressed as
X = Ad time
2X+6= Programming
Total = 30

X+2x+6=30
Simplified is 3x + 6 = 30
Subtract 6 from both sides 3X = 24
Divide both sides by 3 and X=8

Since X is ad time we know that ad time is 8 minutes
Programming is 2X+6 which is 2(8)+6 = 22 minutes

I hope that helps

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Ryan has some nickels and dimes. Altogether, he has 34 coins that total $2.60. Write the system of equations to determine how many of each coin he has.

Answers

34= n+d
2.60=.05n+.1d

To find the amount of dimes that Ryan uses, I used (2.60/0.10) to get 26 dimes, meaning that there are also 8 nickels.

So in total, you have 26 dimes and 8 nickels

Hope this helps

Let W be a point between points U and V on . If UV = 13, UW = 2y – 9, and WV = y – 5, solve for y.

Answers

Answer:

The value of y is 9.

Step-by-step explanation:

Given : W be a point between points U and V also, UV = 13, UW = 2y – 9, and WV = y – 5

We have to solve for y.

Since, W is a point between points U and V .

Then distance of point W from U and distance of point from V is equal to the distance of UV.

Then, UW + WV = UV

Substitute , the values, we get,

Then 2y – 9 + y – 5 = 13

Solving for y , we get,

⇒ 3y - 14 = 13

⇒ 3y = 13 + 14

⇒ 3y = 27

⇒ y = 9

Thus, the value of y is 9.

you would do 9/2
9/2=4.5
2*4.5=9

A pilot flew a jet from location A to B, a distance of 2500 meter,on the return trip the average speed was 20 percent faster than the outbound speed,the round-trip took 9 hours 10 minutes . What is the jet's speed from A to B.

Answers

Answer: The jet's speed from A to B would be 5.5 km/hr.

Step-by-step explanation:

Since we have given that

Distance = 2500 meter

Outbound speed be x

Average speed be $(100+20)/(100)x=(120)/(100)x=1.2x$

Time = 9 hours 10 minutes = $9(10)/(60)=9(1)/(6)=(55)/(6)$

According to question, it becomes,

$(2.5)/(x)+(2.5)/(1.2x)=(55)/(6)\n\n(1.2x+x)/(1.2x^2)=(55)/(6* 2.5)\n\n(2.2x)/(1.2x^2)=(11)/(3)\n\n(2.2)/(1.2x)=(11)/(3)\n\n2.2* 3=1.2x\n\n6.6=1.2x\n\n(6.6)/(1.2)=x\n\nx=5.5\ km/hr$

Hence, the jet's speed from A to B would be 5.5 km/hr.

What is the product of 2/8 and 3/5?
a. 7/11
b. 5/12
c. 3/20
d. 5/13

Answers

2/8 × 3/5
1/4 × 3/5
3/20

The answer is: 3/20.

What is the difference between -3 and five a number line

Answers

The answer to you’re question is 8

What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?

Answers

the nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2

the sum of a geometric seequence is
$S_(n)=(a_(1)(1-r^(n)))/(1-r)$
a1=1
r=2
we want to find $S_(10)$ (since we minus 1, the highest exponet is 9 so add 1 to make it correct)

$S_(10)=(1(1-2^(10)))/(1-2)$
$S_(10)=((1-1024)/(-1)$
$S_(10)=((-1023)/(-1)$
$S_(10)=1023$

Hello,

$1+2+2^2+2^3+...+2^9=(2^(10)-1)/(2-1)=1023$

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