MATHEMATICS HIGH SCHOOL

Evaluate the log without a calculator ( Show your work )

$log_(25) (1)/(5)$

Answers

Answer 1

Answer:

Answer:

$\log_(25)((1)/(5))=-(1)/(2)$

Step-by-step explanation:

Let

$\log_(25)((1)/(5))=x$

We rewrite as an exponential equation to obtain;

$(1)/(5)=25^x$

We rewrite both sides of the equation as an index number to base 5.

$5^(-1)=5^(2x)$

Since the bases are the same, we equate the exponents to obtain;

$-1=2x$

Divide both sides by 2;

$x=-(1)/(2)$

Answer 2

Answer: log 1/5 base 25
25^x=1/5
thinking of number that satisfy it
it is =-1/2

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What is the gcf of 18,54, and 72

Answers

I think its 9 because 9 times 2 is 18 9 times 6 is 54 and 9 times 8 is 72

A cab charges $1.45 for the flat fee and $0.55 for each mile. Write and solve an inequality to determine how many miles Ariel can travel if she has $35 to spend. $1.45 + $0.55x ≥ $35; x ≥ 61 miles $1.45 + $0.55x ≤ $35; x ≤ 61 miles $0.55 + $1.45x ≥ $35; x ≥ 23 miles $0.55 + $1.45x ≤ $35; x ≤ 23 miles

Answers

Answer:

Step-by-step explanation:

To answer this question you first need to know what the inequality symbols mean!

≤ Less than or equal to

≥ Greater than or equal to

So if Ariel has $35 this mean the following:

$1.45 is the flat fee or y-intercept

$0.55 is the slope

This mean the following:

$1.45 + $ 0.55x ≤ $35

$0.55x ≤ $33.55

x≤61

Find the simplified form of the expression. Give your answer in scientific notation.(4x10^10)(9x10^-5)

Answers

It's answer will be 36x10^5As we have(4x10^10)(9x10^-5)All terms of this expression are being multipliedSo we will solve it in two parts, simple terms and terms having powers(4x9)(10^10x10^-5)As we know when same terms having some powers are multiplied, their powers are added(36)(10^(10-5))(36)(10^5)So it will become36x10^5

Answer:

The answer in C

Step-by-step explanation:

What is 15% of 120 and how do you do it

Answers

15%*120=15/100*120=15/10*12 ( u can cancel 1 0 from 100 &120)=3/2*12( by cancelling by 5)=3*6( by cancelling by 2 )=18 ans,,

The Polleys want to put in a swimming pool next summer. They need to save $6,000 over 12 months in order to achieve this goal. They set aside the same amount each month and after 7 months discovered they have saved $3,100. The Polleys know that they must adjust their plan in order to meet their goal, so they come up with the following options:Option A: Save the original amount each month but put the pool in one month later than originally planned.

Option B: Increase savings each month by $100 from their original plan

Answers

Answer:

Neither option A nor option B will allow them to meet their goal.

Step-by-step explanation:

Consider the provided information.

The Polleys want to put in a swimming pool next summer. They need to save $6,000 over 12 months in order to achieve this goal.

They set aside the same amount each month and after 7 months discovered they have saved $3,100. Now he left with 5 months (∴7+5=12 months)

Let x is the amount he was saving each month. He saved x amount for 7 months and after 7 months he has $3100.

$7x=3100$

$x=442.86$

He saved approximately $442.86 each month.

Option A Save the original amount each month but put the pool in one month later than originally planned.

That means the number of month he has now 5+1=6.

Now find how much he can save in 6 months if he save $442.86 per month.

6×442.86=2657.16

Now add his all savings as:

$3100+$2657.16=$5757.16

Thus, the option A will not allow him to meet his goal.

Now consider the option B) Increase savings each month by $100 from their original plan.

Previously he was saving $442.86 each month now increase this number by $100.

$442.86+$100=$542.86

In 5 months he can save:

5×542.86=$2714.3

Now add his all savings as:

$3100+$2714.3= 5814.3

Thus, the option B will not allow him to meet his goal.

Answer:

its D

Step-by-step explanation:

What do antibodies do?engulf and destroy pathogens
produce immature cells that become b cells
attach to cells with the corresponding antigen
produce antigens

Answers

I'm not completely sure but attatch to cells with the corresponding antigen

Answer:

attach to cells with corresponding antigen

Step-by-step explanation:

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