What two numbers add up to 20 but multiply to 75?

Answers

Answer 1
Answer: First you find all the numbers that multiply to get 75.

75 x 1
25 x 3
15 x 5

Then find out which two add together to get 20.

75 + 1 = 76
25 + 3 = 28
15 + 5 = 20

So the answer would be 15 and 5.
Answer 2
Answer: 15 and 5 because 15 times 5 is 75 and 15 plus 5 is 20

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After paying eight dollars for the pie, Mike has eighty - one dollars left, his friend has thirteen dollars. How much money did he have before buying the pie

Answers

Answer:

__ - 8=81

unsure if we're adding his friend but for this i assume no,

81+ 8 = 89

so its either 89 or

89+13=102

Explain how you would go about graphing this equation? What would be your first step and how would you go from there? Y=4x+6 *

Answers

Step-by-step explanation:

First I would look at the y intercept. In a linear equation, y = mx + b, b is the y-intercept and m is the slope. This means that (0,6) is a point on the line since at a y-intercept, the x value is 0. First you should plot this point.

Next, the slope is 4, meaning that for every 1 unit to the right, the line rises 4 units. You can count 1 to the right and 4 up from the y-intercept, which gives you (1,10), a second point on the line. After this, you can connect the two points and there you go, you have a graph!

I need help plzzzzz​

Answers

Answer:

A

Step-by-step explanation:

Given

f(x) = (3+x)/(x-3)

To evaluate f(a + 2), substitute x = a + 2 into f(x)

f(a + 2) = (3+a+2)/(a+2-3) = (5+a)/(a-1) → A

A certain species of tree grows an average of 0.5 cm per week. Write an equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 800 centimeters tall.

Answers

You would turn this into a function f(x). So the constant rate (or slope) is 0.5, so you start off with f(x)=0.5x. But you know that it starts at 8000, which is your intercept. So your final result is
F(x)= 0.5x +8000

Determine the value of k so that 2x^2+kx+5=0 has each type of solutions: 2 real solutions:
2complex,nonreal solutions:
Exactly 1 real solution:

Answers

2x^2+kx+5=0 \n \na=2 \n b=k \n c=5 \n \Delta=b^2-4ac=k^2-4 * 2 * 5=k^2-40

When the discriminant Δ is greater than 0, the equation has 2 real solutions:
k^2-40 > 0 \nk^2>40 \nk>√(40) \ \lor \ k<-√(40) \nk>2√(10) \ \lor \ k<-2√(10) \n\boxed{k \in (-\infty,-2√(10)) \cup (2√(10), +\infty)}

When the discriminant Δ is less than 0, the equation has 2 complex and no real solutions:
k^2-40<0 \nk^2<40 \nk<√(40) \ \land \ k>-√(40) \nk<2√(10) \ \land \ k>-2√(10) \n\boxed{k \in (-2√(10),2√(10))}

When the discriminant Δ is equal to 0, the equation has exactly 1 real solution:
k^2-40=0 \nk^2=40 \nk=√(40) \ \lor \ k=-√(40) \nk=2√(10) \ \lor \ k=-2√(10) \n\boxed{k \in \{ -2√(10), 2√(10) \} }

Some students attend school 180 of the 365 days in a year. About what part of the year do they attend school?

Answers

If 365 is 100% and 180 is about 50% then your answer is 50%.