two angles are supplementary the first angle measures 40 degrees what is the measurement of the second angle

Answers

Answer 1

Answer: Supplementary angles add up to 180
40+x=180
x=140

Answer 2

Answer: The answer would be 160

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Natalie wants to measure the width of a river. She marks off two right angles, as shown in the figure. The base of the larger triangle has a length of 58m, and the base of the smaller triangle has a length of 26m. The height of the smaller triangle is 21.3m. How wide is the river? Round your answer to the nearest meter.

Answers

Given:
Larger Triangle : base = 58 m ; height = x
Smaller Triangle: base = 26 m; height = 21.3 m

x:58 = 21.3:26
26x = 58*21.3
26x = 1,235.4
x = 1,235.4 / 26
x = 47.515

The river is 48 meters wide.

If A ⊂ B and A ∩ B = θ then which of the following can be concluded about the sets A and B?Set A has more elements in it than set B.
Set A is the set containing zero.
Set A is the empty set.
Both sets A and B are the empty set.

Answers

A ⊂ B means all of A is in B

but then it says A ∩ B = θ meaning they have nothing in common, ie, none of A is in B or vice versa

A must be the empty set for both these conditions to hold. B could be anything you want. B could be empty, or it could not be. It's impossible to tell.

For certain, A must be empty. Which is why the answer is choice C

Each marble bag sold by Melissa's Marble Company contains 3 orange marbles for every 5 blue marbles. If a bag has 24 orange marbles, how many blue marbles does it contain?

Answers

3/5=24/x. cross multiply, you get 120=3x. divide by 3, x = **40**

3:5

3 to 5

3
-----
5

First we will divide to see who many sets of orange there are in the bag.

24 ÷ 3 = 8

Since there are 8 sets of orange we will multiply8 by 5 since for every 3 orange marbles there are 5 blue marbles.

8 × 5 = 40

SO, a bag contains 24 orange marbles and 40 blue marbles.

Hope i helped ya!

How would you find the zero of f (x)=16x^4 - 9x^2

Answers

$f (x) = 16x ^ 4 - 9x ^ 2 \n \n16x ^ 4 - 9x ^ 2=0\n \nx^2(16x^2-9)=0 \n \nx^2 =0 \ \ or \ \ 16x^2-9=0\n \n x=0 \ \ or \ \ (4x-3)(4x+3)=0\n \n x=0 \ \ or \ \ 4x-3=0 \ \ or \ \ 4x+3 =0\n \nx=0 \ \ or \ \ 4x=3 \ \ / :4 \ \ or \ \ 4x=-3\ \ / :4 \n \n x=0 \ \ or \ \ x=(3)/(4) \ \ or \ \ x=-(3)/(4)$

$f(x)=16x^4-9x^2\n\nf(x)=0\iff16x^4-9x^2=0\n\nx^2(16x^2-9)=0\iff x^2=0\ \vee\ 16x^2-9=0\n\nx=0\ \vee\ 16x^2=9\n\nx=0\ \vee\ x^2=(9)/(16)\n\nx=0\ \vee\ x=-\sqrt(9)/(16)\ \vee\ x=\sqrt(9)/(16)\n\nx=0\ \vee\ x=-(3)/(4)\ \vee\ x=(3)/(4)$

There are 18 bikes in the rack. There are 4 more blue bikes than yellow bikes and 2 less yellow bikes than green bikes. How many bikes of each color are in the rack? How do you figure out the problem?

Answers

Their will be the following:

Blue Bikes - 8
Green Bikes - 6
Yellow Bikes - 4

Unfortunately i figured out this problem in my head with guess work.

Hope this has helped in anyway.

1) point R has coordinates of (1,0) point S is symmetric to point R with respect to the line y=-2, what are the coordinates of point S2)point N has coordinates of (-1,2) point M is symmetric to point N with respect to the line y=X, what are the coordinates of point M

3) x^2=36
A. 9sqrt. 2 - 9sqrt. 2
B. 6 - 6
C. 4sqrt. 3 - 4sqrt. 3
D. 18 - 18

4) x^2=90
A. 10 sqrt. 3 - 10 sqrt. 3
B. 3 sqrt. 10 -3 sqrt. 10
C. 3 sqrt. 15- 3 sqrt. 15
D. 45 - 45

Answers

The right answer for the question that is being asked and shown above is that: "C. 4sqrt. 3 - 4sqrt. 3."

The right answer for the question that is being asked and shown above is that: "B. 3 sqrt. 10 -3 sqrt. 10."

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BD bisects ABC, m/ABC =8x, m/ABD=2x + 30. Find m/DBC.