The specific heat capacity of a substance is the amount of energy associated with doing which of the following to 1kg of the substance?
The specific heat capacity of a substance is the amount - 1

Answers

Answer 1
Answer:

Answer:

Raising its temperature by 1^(\circ)C

Explanation:

The specific heat capacity of a substance is defined as the amount of energy needed to raise the temperature of 1 kg of a substance by 1^(\circ)C.

The specific heat capacity of a substance essentially tells us how much energy is needed to heat the substance: the larger it is, the more energy is needed. The amount of energy needed to increase the temperature of a substance is given by

Q=mC_s \DeltaT

where

m is the mass of the substance

Cs is the specific heat capacity

\Delta T is the temperature variation of the substance

Answer 2
Answer:

Answer:

Raising its temperature by 1 C

Explanation:

A P E X


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The spring is compressed a total of 3.0 cm, and used to set a 500 gram cart into motion. Find the speed of the cart at the instant it is released, assuming all the elastic potential energy is converted.

Answers

Answer:

1.15 m/s

Explanation:

Part of the question is missing. Found the missing part on google:

"1. A hanging mass of 1500 grams compresses a spring 2.0 cm.   Find the spring constant in N/m."

Solution:

First of all, we need to find the spring constant. We can use Hooke's law:

F=kx

where

F=mg=(1.5 kg)(9.8 m/s^2)=14.7 N is the force applied to the spring (the weight of the hanging mass)

x = 2.0 cm = 0.02 m is the compression of the spring

Solving for k, we find the spring constant:

k=(F)/(x)=(14.7)/(0.02)=735 N/m

In the second part of the problem, the spring is compressed by

x = 3.0 cm = 0.03 m

So the elastic potential energy of the spring is

U=(1)/(2)kx^2=(1)/(2)(735)(0.03)^2=0.33 J

This energy is entirely converted into kinetic energy of the cart, which is:

U=K=(1)/(2)mv^2

where

m = 500 g = 0.5 kg is the mass of the cart

v is its speed

Solving for v,

v=\sqrt{(2K)/(m)}=\sqrt{(2(0.33))/(0.5)}=1.15 m/s

Every 6 seconds a pendulum completes one cycle. What are the period and frequency of this pendulum?

Answers


The period is the time it takes any repeating process
to complete one cycle.  You just told us what it is for the
pendulum . . . 6 seconds.

The frequency is the reciprocal of the period.  For the pendulum,
that's

                 1 / (6 sec) = (1/6) per second = 1/6 Hertz .

The period is 2.4 seconds and the frequency is I believe 1/6 I'm not entirely sure since I don't think this question has enough information.

A person is pulled to the right on a sled (total mass of 52.9 kg) across the surface of a frozen pond with a force of 67.7 Newtons so that they move with a constant velocity. What is the force of friction acting on the sled?

Answers

Answer:

67.7 N

Explanation:

Draw a free body diagram of the person on the sled.  There are four forces:

67.7 N  to the right,

friction force to the left,

weight force down,

and normal force up.

Constant velocity means 0 acceleration.

Sum of the forces in the x direction:

∑F = ma

67.7 N − F = 0

F = 67.7 N

Explain why fluids travel faster near the center of pipes and tubes than at the edges

Answers

I think fluids travel faster near the center of pipes and tubes better than at the edges because they are able to travel much faster, and smoother in the center rather than the edges because the fluids have to turn, which could cause the rest of the incoming fluids to stop, which would make it much slower when traveling through the edges than through the center. 

Explain why the gravitational acceleration of any object near earth is the same matter what was the mass of the object

Answers

It takes greater force to accelerate an object that has more mass. But the gravitational force between the Earth and an object is greater when the object hass more mass. It works out just right to make any object with any mass accelerate at the same rate.

What type of wave is produced by a radio transmitter antenna

Answers

Answer:

Radio Waves...

Explanation:

When there is electricity flowing into the transmitter antenna makes electrons vibrate up and down it, producing radio waves...

I hope this helps you with what you need!!!